All categories

2 years ago

WILL GIVE BRAINLIEST. please help

Mathematics

1 answer:

kondor19780726 [428]2 years ago

4 0

Answer:

x = 11.4 m

y = 21 m

man's shadow = 9.6 m

Step-by-step explanation:

measure of third angle must be 50 degrees (180 - (40 + 90))

you can take tan50° = 15/y and 'y' will equal approx. 21

to find 'x' you can take tan21° = (21-x) /25 and 21 - x = 25 · tan21°

21 - x = 9.6

-x = -11.4

x = 11.4

man's shadow is the difference of 21 and 11.4, which is 9.6

You might be interested in

WILL GIVE BRAINLIEST Which expression is equivalent to x + 11?

larisa [96]

Answer:

11+x because the equation is reversabel.

Step-by-step explanation:

6 0

2 years ago

How do you tell if an equation is linear or not????

Tasya [4]

You can tell if the equation is linear or not if the equation makes a straight line on a graph.

3 0

3 years ago

Read 2 more answers

Sara wants to keep her phone bill under $40 each month. There is a flat fee of $34 and she is charged $0.05 per text message, t.

alukav5142 [94]

Answer:

320 messages

Step-by-step explanation:

20 messages per dollar,

20 x 16 equals 320

8 0

2 years ago

Help pls and explain thank you :)

Solnce55 [7]

25 because Becky read 45 and Jason read 20

45-20 = 25

5 0

2 years ago

Read 2 more answers

A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

4 0

3 years ago