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spayn [35]
4 years ago
8

Find the equation of the line that has slope -5/7 and which passes through (-1,-2)

Mathematics
2 answers:
bonufazy [111]4 years ago
5 0
Y=mx+b, m=slop and b = intercept point=(-1,-2)
=> -2 = -5/7(-1)+b => b= -2 -5/7= -21/7
=> y=-5/7x - 21/7
pickupchik [31]4 years ago
3 0
Use the formula

y+2=-5/7(x+1)
solve and you will get the equation which is
f(x)=-5/7(x)-19/7
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Please help <br><br> questions 12,14,16
notka56 [123]

Answer:

12) y=3x-15

14) y=-1/2x

16) y=13x-105

Step-by-step explanation:

Parallel lines always have the same slopes but different y-intercepts. So, we can make the equation (b is y-intercept of new equation):

12) y=3x+b

14) y=-1/2x+b

16) y=13x+b

now, we can plug in each of the coordinates given to these equations.

12) (4,-3): 4 is x, -3 is y.

       -3=3(4)+b

      simplify: b= -15

14) (-4,2): -4 is x, 2 is y

      2=-1/2(-4)+b

        simplify: b=0

16) (9,12): 9 is x, 12 is y

       12=13(9)+b

       simplify: b=-105

Now, plug in those numbers to your equation for b value.

12) y=3x-15

14) y=-1/2x

16) y=13x-105

*for 14 we don't need to write anything after -1/2x because b=0*

3 0
3 years ago
In the funny elementary school cafeteria, lunch for 100 people is served. But it is today turvy, and the waiters are acting funn
Oliga [24]

Answer:

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Step-by-step explanation:

All the plates were upside down, then every third waiter turned the third plate upwards, the fourth waiter turned every plate upward and so on, the pattern continued until the 100th waiter turned the 100th plate upward. The pattern was finished and all the plates were placed normally, right side up.

5 0
3 years ago
Factor:<br> 4tan^2x-(4)/(cotx)+sinx(cscx) ...?
lisov135 [29]
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4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin... 


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(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot... 


Combine the numerators of all expressions that have common denominators. 
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(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
8 0
3 years ago
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Korvikt [17]

Answer:

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Step-by-step explanation:

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70 is the answer
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