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spayn [35]
3 years ago
8

Find the equation of the line that has slope -5/7 and which passes through (-1,-2)

Mathematics
2 answers:
bonufazy [111]3 years ago
5 0
Y=mx+b, m=slop and b = intercept point=(-1,-2)
=> -2 = -5/7(-1)+b => b= -2 -5/7= -21/7
=> y=-5/7x - 21/7
pickupchik [31]3 years ago
3 0
Use the formula

y+2=-5/7(x+1)
solve and you will get the equation which is
f(x)=-5/7(x)-19/7
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The answer should be -14(2+v^6) if I’m correct
6 0
3 years ago
How to divide 4.48 ÷7​
Rina8888 [55]

Answer:

<h2>0.64</h2>

Step-by-step explanation:

4.48/7

7 into 4 (0 times)

Bring next number down 4.48 ⬇️

7 into 44 (6 times, 2 left over)

Bring next number down 4.48 ⬇️

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Answer 0.64

I'm always happy to help :)

5 0
3 years ago
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Is 1.7x^2 + 3.5 a cubic polynomial?
devlian [24]

Answer:

No, it is not.

Step-by-step explanation:

This is because if you look at the expression, there is no term that is raised to the cube root. As a result, this isn't a cubic polynomial. However, this would be a quadratic polynomial cause the highest raised exponent is 2, which is the number for quadratic.

If you liked my response, please consider giving me a Brainliest! Thanks!

8 0
3 years ago
URGENT HELP PLEASE!
Vaselesa [24]

Answer:

(a) x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b) x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}

Step-by-step explanation:

It is given that 0\leq x\leq 2\pi.

(a)

\sqrt{2}\sin 2x=1

\sin 2x=\dfrac{1}{\sqrt{2}}

\sin 2x=\dfrac{\pi}{4}

2x=\dfrac{\pi}{4},\dfrac{3\pi}{4},\dfrac{9\pi}{4},\dfrac{11\pi}{4}     [\because \sin x=\sin y\Rightarrow x=n\pi+(-1)^ny]

x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b)

\csc^2 x-\csc x-2=0

\csc^2 x-2\csc x+\csc x-2=0

\csc x(\csc x-2)+1(\csc x-2)=0

(\csc x+1)(\csc x-2)=0

\csc x=-1\text{ or }\csc x=2

\sin x=-1\text{ or }\sin x=\dfrac{1}{2}         [\because \sin x=\dfrac{1}{\csc x}]

x=\dfrac{3\pi}{2}\text{ or }x=\dfrac{\pi}{6},\dfrac{5\pi}{6}

Therefore, x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}.

5 0
2 years ago
What is the slope of the line passing through the points (3,5) and (-1,7)?
Maurinko [17]

-1/2

To find the slope of the line between two points, we use the equation (y2-y1)/(x2-x1)

Substitute the values given for the xs and ys:

(7-5)/(-1-3)

2/(-4)

simplify: -1/2

3 0
3 years ago
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