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3 years ago

Find the equation of the line that has slope -5/7 and which passes through (-1,-2)

Mathematics

2 answers:

bonufazy [111]3 years ago

5 0

Y=mx+b, m=slop and b = intercept point=(-1,-2)
=> -2 = -5/7(-1)+b => b= -2 -5/7= -21/7
=> y=-5/7x - 21/7

pickupchik [31]3 years ago

3 0

Use the formula

y+2=-5/7(x+1)
solve and you will get the equation which is
f(x)=-5/7(x)-19/7

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Alecsey [184]

Answer:

Step-by-step explanation:

You can start this in may ways but let's start by isolating one of the parenthesis:

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x³ - 5x + x = 3

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2 years ago

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2 years ago

Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?

OlgaM077 [116]

Answer:

$a_n = 16(\frac{1}{4})^{n - 1}$

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = $\frac{1}{16}$

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = $ar^{n - 1}$ , where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

$\frac{1}{16} = a*\frac{1}{4}^{5 - 1}$

$\frac{1}{16} = a*\frac{1}{4}^{4}$

$\frac{1}{16} = a*\frac{1}{256}$

$\frac{1}{16} = \frac{a}{256}$

Cross multiply

$1*256 = a*16$

Divide both sides by 16

$\frac{256}{16} = \frac{16a}{16}$

$16 = a$

$a = 16$

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = $ar^{n - 1}$

nth term = $16*\frac{1}{4}^{n - 1}$

$a_n = 16(\frac{1}{4})^{n - 1}$

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2 years ago