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What are the coordinates of A'and B'when AB is reflected in the y-axis? Show your work or explain

vaieri [72.5K]

The coordinates of A'and B'when AB is reflected in the y-axis are; (-2,5) and (-6,3).

<h3>What are the coordinates of A'and B'when AB is reflected in the y-axis?</h3>

According to the task content, it follows that the reflected points A' and B's coordinates are required.

From the graph, the coordinates of A= (2,5) and B= (6,3).

On this note, the coordinates of A' and B' upon reflection over the y-axis is; (-2,5) and (-6,3) respectively.

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7 0

1 year ago

Using the table below, determine how much you will receive in dividends for the year from Cisco Systems given that you currently

evablogger [386]

Answer: A. $15

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find area of the shape.<br> 30 mm<br> 20 mm<br> User = 3.14

Elodia [21]

Answer:

Area is calculated by multiplying the length of a shape by its width. In this case, we could work out the area of this rectangle even if it wasn't on squared paper, just by working out 5cm x 5cm = 25cm² (the shape is not drawn to scale.

Step-by-step explanation:

6 0

2 years ago

A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his pro

Anestetic [448]

Answer:

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

Step-by-step explanation:

Given that, a homeowner plans to enclose a 200 square foot rectangle playground.

Let the width of the playground be y and the length of the playground be x which is the side along the boundary.

The perimeter of the playground is = 2(length +width)

=2(x+y) foot

The material costs $1 per foot.

Therefore total cost to give boundary of the play ground

=$[ 2(x+y)×1]

=$[2(x+y)]

But the neighbor will play one third of the side x foot.

So the neighbor will play $=\$(\frac13x)$

Now homeowner's total cost for the material is

$=\$[ 2(x+y)-\frac13x]$

$=\$[2x+2y-\frac13x]$

$=\$[2y+x+x-\frac13x]$

$=\$[2y+x+\frac{3x-x}{3}]$

$=\$[2y+x+\frac{2}{3}x]$

$=\$[2y+\frac53x]$

$\therefore C(x)=2y+\frac53x$

where C(x) is total cost of material in $.

Given that the area of the playground is 200.

We know that,

The area of a rectangle is =length×width

=xy square foot

∴xy=200

$\Rightarrow y=\frac{200}{x}$

Putting the value of y in C(x)

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

The domain of C is $(0,\infty )$ .

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

Differentiating with respect to x

$C'(x)= - \frac{400}{x^2}+\frac53$

Again differentiating with respect to x

$C''(x) = \frac{800}{x^3}$

To find the critical point set C'(x)=0

$\therefore 0= - \frac{400}{x^2}+\frac53$

$\Rightarrow \frac{400}{x^2}=\frac{5}{3}$

$\Rightarrow x^2 =\frac{400\times 3}{5}$

$\Rightarrow x=\sqrt{240}$

$\Rightarrow x=15.49 \approx15.5$

Therefore

$\left C''(x) \right|_{x=15.5}=\frac{800}{15.5^3}>0$

Therefore at x= 15.5 , C(x) is minimum.

Putting the value of x in $y=\frac{200}{x}$ we get

$\therefore y=\frac{200}{15.5}$

=12.9

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

6 0

3 years ago

Brandon enters bike races.He bikes 8 1/2 miles every 1/2 hour. complete a table to find how far Brandon bikes for each time inte

MissTica

12. Since there is no table given I will assume that what you want me to do is to show that Unit rate of Brandon’s biking. SO here are the data that we need: => 8 and ½ miles = 8.5 miles => ½ hour = .5 hours or 30 minutes Now, let’s solve for the unit rate => SO in every 30 minutes he bikes around 8.5 miles => Since 1 hour is equals to 30 minutes, simply multiply 8.5 by 2 => 8.5 * 2 = 17miles => 17 miles / hour

4 0

2 years ago

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