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3 years ago

Help me now please thank you so much

Mathematics

2 answers:

mr Goodwill [35]3 years ago

8 0

Answer:

Step-by-step explanation:

6square-7(14-3square)

36-7(14-9)

36-7multiply by 5

36-45

=. -9

lara31 [8.8K]3 years ago

4 0

Hey hun!!! Answer is -9!! have an amazing day.

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PLEASE HELP!!

Bezzdna [24]

Answer:

$y=-\dfrac{9}{40}x^2+\dfrac{441}{40}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}$

Step-by-step explanation:

If a parabola has its vertex on the y-axis, then its equation is

$y=ax^2+b$

This parabola passes through the point R(3,9), then

$9=a\cdot 3^2+b\\ \\9=9a+b$

The area of the right triangle PQR is

$A_{PQR}=\dfrac{1}{2}\cdot PQ\cdot QR$

Find PQ and QR, if $P(x_1,0),\ Q(3,0),\ R(3,9):$

$PQ=\sqrt{(x_1-3)^2+(0-0)^2}=|x_1-3|\\\\QR=\sqrt{(3-3)^2+(0-9)^2}=9$

Now,

$40.5=\dfrac{1}{2}\cdot |x_1-3|\cdot 9\\ \\90=9|x_1-3|\\ \\|x_1-3|=10\\ \\x_1-3=10\ \text{or}\ x_1-3=-10\\ \\x_1=13\ \text{or }x_1=-7$

We get two possible points $P_1(-7,0)$ and $P_2(13,0).$

For point $P_1:\\$

$0=a\cdot (-7)^2+b\\ \\49a+b=0$

So,

$b=-49a\\ \\9=9a-49a\\ \\-40a=9\\ \\a=-\dfrac{9}{40}\\ \\b=\dfrac{441}{40}\\ \\y=-\dfrac{9}{40}x^2+\dfrac{441}{40}$

For point $P_2:\\$

$0=a\cdot (13)^2+b\\ \\169a+b=0$

So,

$b=-169a\\ \\9=9a-169a\\ \\-160a=9\\ \\a=-\dfrac{9}{160}\\ \\b=\dfrac{1,521}{160}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}$

5 0

3 years ago

I don't get this. I could really use help.

olga nikolaevna [1]

The y intercept is what the y value is when x is 0.

Set X to 0 and solve:

-2/9(0) + 1/3

0 + 1/3 = 1/3

The y-intercept is 1/3

6 0

3 years ago

This not from a quiz or exam its practice stop taking down my question because of that

Novay_Z [31]

We’ll try another app

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tia_tia [17]

Answer:

Vertex= (0,4)

Domain= x: all real number

Range: ( - ∞, 4] or y ≤ 4

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3 years ago

A right triangle is revolved around the y axis. describe the solid of revolution

MaRussiya [10]

Answer:

CONE

Step-by-step explanation:

CONE

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