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Citrus2011 [14]
3 years ago
15

Please help me with my algebra homework thank you

Mathematics
2 answers:
kumpel [21]3 years ago
7 0

Answer:

a.) 5x

b.) 6xy

c.) 6xy

Step-by-step explanation:

5 * x = 5x

6 * x * y = 6xy

2 * x * 3 * y = 6xy

Lina20 [59]3 years ago
3 0

Step-by-step explanation:

  • a. 5x.
  • b. 6xy
  • c. 6xy

hope it helps. :)

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Plz Answer ASAP
SpyIntel [72]
D and C because that the answer
3 0
3 years ago
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Can someone check this for me thanks.
kirill115 [55]
You are right all the way
8 0
3 years ago
Select the graph of the solution. Click until the correct graph appears. 3x + 1 < 7 (line graph)
WARRIOR [948]
3x + 1 < 7...subtract 1 from both sides
3x < 7 - 1
3x < 6 ...divide both sides by 3
x < 6/3
x < 2

there will be an open circle on 2....because the problem has no equal sign...the line will be shaded to the left...because it is less then.
6 0
3 years ago
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What percentage of this shape is shaded?
Lilit [14]

Answer:

50%

Step-by-step explanation:

8 0
3 years ago
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
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