C if you look at the square you can see that b b =bb and not Bb
The Hardy-Weinberg equation is as follows:


Where:
(convert all % to decimals)
p= homozygous dominant
q= homozygous recessive
pq= heterozygous
While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.
Using the 1st equation, we can solve for the other dominant/recessive frequency:
1-0.2=0.8
Meaning that:
p= 0.8 & q=0.2
If the heterozygouz frequency is 2pq, then it becomes a simple "plug & chug" sort of approach.
2(0.8)(0.2)= 2(0.16)= 0.32
So, the heterozygous frequency would be:
0.32
Hope this helps!
The flooding of half part of the forest have successful separate the population of frogs in that ecosystem into two different set of frogs. This is an example of allopatric speciation, that is, the population become separated as a result of geographical barrier. This separation will make the two set of frog population to become new species. On the long run, the two species may become unable to relate sexually.
The comparison and contrast between the raft and the shore has something to do with freedom. On the river, Huck and Jim are free from the legal, societal and cultural structures which is the opposite if they were on the shore. However, their freedom on the raft was only for a short period of time. When<span> they went back on the shore, they were once again forced to comply with the </span>laws. The<span> similarities between the raft and the shore </span>are<span> natural. They are both are connected with geographical features.</span><span> </span>
<span>The position of the carbonyl group.
Both aldoses and ketoses are monosaccharides. They are simple sugars with a Carbon chain. The difference is what's in the position of the carbonyl group: aldoses have an aldehyde group while ketoses have aketone group.</span>