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cricket20 [7]
3 years ago
8

Will give brainliest :)

Mathematics
1 answer:
Whitepunk [10]3 years ago
5 0

Answer:

90 degrees

Step-by-step explanation:

BCO = 66

The whole ABC is 180

So BCO and  BDO = 90

Therefore BAO must = 90 degrees

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A school gym is divided for a fair by bisecting its width and its length. Each half of the length is then​ bisected, forming 8 s
SVETLANKA909090 [29]

Answer:

Dimensions will be

New Length= x/16 units

New width = y/2 units

Area=xy/32 square units

Step-by-step explanation:

Lets assume the dimensions of the school gym to be ;

Length= x

width= y

Length and width are first bisected for a fair.This means by a half

Length will be =x/2

Width will be =y/2

Then the length is divided to form 8 sections that are equal, which will ;

(x/2)÷8

x/2 * 1/8 = x/16 units

New length = x/16 units in dimension

New width will be y/2 units in dimension

Area of each section will be;

length by width

(x/16 )*(y/2)

=xy/32 square units

7 0
3 years ago
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Midpoints...........
telo118 [61]

Answer:

OP = 2

Step-by-step explanation:

please mark me brainliest and 5 star

3 0
3 years ago
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A. How far is the spot on the beach from the parking lot?
Afina-wow [57]

The altitude of the right triangle is the geometric mean of the 2 parts of the side it separates.

a. The answer would be sqrt(18*32)=24

The question to the second question can be answered by using the Pythagorean theorem.

32^2+24^2=1600=40^2

b. The answer would be sqrt40^2=40

7 0
3 years ago
Please help out , i’ll mark the brainliest answer
Len [333]

Answer:

Step-by-step explanation:

7) The tangent angles are 90° each.

The angles of a quadrilateral add up to 360°, so ? = 360°-90°-90°-73° = 107°.

8)  Solve this the same way as question 7). ? = 360°-90°-90°-57° = 123°.

Questions 9) and 10) are cut off, so I assume you don't need to know those.

4 0
3 years ago
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Please Help me I'm stuck
Tresset [83]

When reflecting across the Y axis, the Y values remain the same.

Now if you were reflecting across Y = 0, the x values would just be inverse ( opposite signs).

So this triangle if reflected across Y = 0 the new vertices would be (4,4) (2,3) and (5,2)

Now since the reflection line is y = -1, which is a one unit shift to the left of y = 0, subtract 1 unit from each X value.

The locations are now: A'(3,4), B'(1,3) and C'(4,2)

4 0
4 years ago
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