Answer:
Dimensions will be
New Length= x/16 units
New width = y/2 units
Area=xy/32 square units
Step-by-step explanation:
Lets assume the dimensions of the school gym to be ;
Length= x
width= y
Length and width are first bisected for a fair.This means by a half
Length will be =x/2
Width will be =y/2
Then the length is divided to form 8 sections that are equal, which will ;
(x/2)÷8
x/2 * 1/8 = x/16 units
New length = x/16 units in dimension
New width will be y/2 units in dimension
Area of each section will be;
length by width
(x/16 )*(y/2)
=xy/32 square units
Answer:
OP = 2
Step-by-step explanation:
please mark me brainliest and 5 star
The altitude of the right triangle is the geometric mean of the 2 parts of the side it separates.
a. The answer would be sqrt(18*32)=24
The question to the second question can be answered by using the Pythagorean theorem.
32^2+24^2=1600=40^2
b. The answer would be sqrt40^2=40
Answer:
Step-by-step explanation:
7) The tangent angles are 90° each.
The angles of a quadrilateral add up to 360°, so ? = 360°-90°-90°-73° = 107°.
8) Solve this the same way as question 7). ? = 360°-90°-90°-57° = 123°.
Questions 9) and 10) are cut off, so I assume you don't need to know those.
When reflecting across the Y axis, the Y values remain the same.
Now if you were reflecting across Y = 0, the x values would just be inverse ( opposite signs).
So this triangle if reflected across Y = 0 the new vertices would be (4,4) (2,3) and (5,2)
Now since the reflection line is y = -1, which is a one unit shift to the left of y = 0, subtract 1 unit from each X value.
The locations are now: A'(3,4), B'(1,3) and C'(4,2)
