Question

Need help asappppppp​

Answer 1

Given:

The right triangular prism.

Height of prism = 28 in.

Hypotenuse of base = 25 in.

leg of base = 24 in.

To find:

The lateral surface area of the prism.

Solution:

Pythagoras theorem:

$Hypotenuse^2=Perpendicular^2+Base^2$

Using Pythagoras theorem in the base triangle, we get

$25^2=24^2+Base^2$

$625-576=Base^2$

$\sqrt{49}=Base$

$7=Base$

The perimeter of the triangular base is:

$P=7+25+24$

$P=56$

Lateral area of a triangular prism is:

$A=Ph$

Where, P is the perimeter of the triangular base and h is the height of the prism.

Putting $P=56,h=28$ in the above formula, we get

$A=56(28)$

$A=1568$

Therefore, the lateral area of the prism is 1568 in².