Answer:
40000×1×9%=3 600 this is for year
Yes I think it is correct.
Answer:
(1,2021)
Step-by-step explanation:
P and q can vary subject to their sum being 2020.
Consider one parabola with p1 and q1 and another with p2 and q2.
y1=(x1)^2+(p1)(x1)+(q1)
y1=(x2)^2+(p2)(x2)+(q2)
At their intersection, the x and y coordinates are the same.
y1=y2=y
x1=x2=x
x^2+(p1)x+(q1)=x^2+(p2)x+(q2)
Solve for x
x(p1-p2)=q2-q1
x=(q2-q1)/(p1-p2)
Use the constraint that p+q=2020 to eliminate p1 and p2.
p1=2020-q1
p2=2020-q2
x=(q2-q1)/(2020-q1-2020+q2)
x=(q2-q1)/(q2-q1)
x=1
Substitute in the equation for y.
y=1^2+p(1)+q
y=2021
For first pound it is = $2.41
For next six, = 0.41 * 6 = $2.46
Remaining = 7.99 - (2.41 + 2.46) = 7.99 - 4.87 = 3.12
Now, additional pounds = 3.12 / 0.39 = 8
Total weight = 1 + 6 + 8 = 15
In short, Your Answer would be 15 pounds
Hope this helps!
Answer:
<em>tanB</em><em>=</em>p/b
tanB=3/4
B=tan-¹(3/4)=17.89=18° is your answer.
