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3 years ago

What’s the answer to six plus negative 3

Mathematics

1 answer:

Alik [6]3 years ago

6 0

6 + (-3) would be the same as just saying 6-3 which would be equal to positive 3

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FIND THE INDICATED PROBABILITY FOR THE FOLLOWING:

luda_lava [24]

The value of the probability P(A) is 0.40

<h3>How to determine the probability?</h3>

The given parameters about the probability are

P(A or B) = 0.6

P(B) = 0.3

P(A and B) = 0.1

To calculate the probability P(A), we use the following formula

P(A and B) = P(A) + P(B) - P(A or B)

Substitute the known values in the above equation

0.1 = 0.3 + P(A) - 0.6

Collect the like terms

P(A)= 0.1 - 0.3 + 0.6

Evaluate the expression

P(A)= 0.4

Hence, the value of the probability P(A) is 0.40

Read more about probability at

brainly.com/question/25870256

#SPJ1

3 0

2 years ago

What is the most simplified version of the expression shown below?

mestny [16]

It’s A. The other ones don’t work.

4 0

3 years ago

Read 2 more answers

Solve this and get 12 points

Pachacha [2.7K]

Answer:

Step-by-step explanation:

First, find <em>x</em>. Since <em>x</em> is the average of the three number, add the three up and then divided by three. Thus:

$x=\frac{13+-16+6}{3}=3/3=1$

<em>y</em> is the cube root of 8. Thus:

$y=\sqrt[3]{8}=2$

So:

$x^2+y^3\\=(1)^2+(2)^3\\=1+8=9$

5 0

3 years ago

Read 2 more answers

400 lbs = ? Tons and 38,600 mg = ? dekagrams

garik1379 [7]

400 lbs = 0.2 tons

38,600 mg = 3.86 dekagrams

Hope it helps!

3 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers