All categories

3 years ago

Jessica locates her garden using a coordinate grid with yards as the units. The two points

Mathematics

1 answer:

Oliga [24]3 years ago

8 0

Answer:

These two corners are $\sqrt{13}$ units apart.

Step-by-step explanation:

Distance between two points:

Suppose we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Approximately how far apart are the two corners?

We have to find the distance between the points (-5,-2) and (-8-3). So

$D = \sqrt{(5-(-8))^2+(-2-(-3))^2} = \sqrt{13}$

These two corners are $\sqrt{13}$ units apart.

You might be interested in

3x-4y=11 <br>3x+2y=2<br>please help, I need to find what the answer is for x and y

Zielflug [23.3K]

Answer:

I have attached a picture of me solving the equation.

Now you must be wondering how I got the answer, well first simplify the expression in y = mx + b. Then graph it on demos. Do the same thing for the other expression. Pick any point that lies on the line. That is your solution to the equation.

The green line is the expression of 3x - 4y = 11. I simplify the equation in y = mx + b giving me y = 3/4x - 11/4.

The orange line is the expression of 3x + 2y = 2. I simplify the equation in y = mx + b giving me y = -3/2x + 1.

Hope this helps, thank you !!

3 0

3 years ago

Membership in an art club is expected to grow by about 4% per month. Currently, there are 350 members in the club. In about how

igomit [66]

500=350(1+0.04/12)^12x
Solve for x
500/350=(1+0.04/12)^12x
X=(Log(500/350)/log(1+0.04/12))/12
X=9 months

6 0

3 years ago

Read 2 more answers

I will mark you brainiest if you can answer this

Vikentia [17]

7 will never equal 8 so there is no solution. so i think it is C

3 0

2 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

zaharov [31]

Answer:

P(61≤ X≤94) = 49.85%

Step-by-step explanation:

From the given information:

The mean of the bell shaped fluorescent light bulb μ = 61

The standard deviation σ = 11

The objective of this question is to determine the approximate percentage of light bulb replacement requests numbering between 61 and 94 i.e P(61≤ X≤94)

Using the empirical (68-95-99.7)rule ;

At 68% , the data lies between μ - σ and μ + σ

i.e

61 - 11 and 61 + 11

50 and 72

At 95%, the data lies between μ - 2σ and μ + 2σ

i.e

61 - 2(11) and 61 + 2(11)

61 - 22 and 61 +22

39 and 83

At 99.7%, the data lies between μ - 3σ and μ + 3σ

i.e

61 - 3(11) and 61 + 3(11)

61 - 33 and 61 + 33

28 and 94

the probability equivalent to 94 is when P(28≤ X≤94) =99.7%

This implies that ,

P(28≤ X≤94) + P(61≤ X≤94) = 99.7%

P(28≤ X≤94) = P(61≤ X≤94) = 99.7 %

This is so because the distribution is symmetric about the mean

P(61≤ X≤94) = 99.7 %/2

P(61≤ X≤94) = 49.85%

5 0

2 years ago

An investment firm invested in two companies last year. They invested $40,000 in company A and made a profit of 15%. They invest

alexira [117]

Answer:

A) $8200.

B) 16.4%

Step-by-step explanation:

Here is the complete question: An investment firm invested in two companies last year. They invested $40,000 in company A and made a profit of 15%. They invested $10,000 in company B and made a profit of 22%.

A) What is the investment firms total profit?

B) What is the percent profit of the total investment?

Given: Company A invested $40000 and made profit of 15%

Company B invested $10000 and made profit of 22%

A) First lets find the profit of company A and B.

Company A= $\frac{15}{100} \times \$ 40000= \$ 6000.$