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Answer: -75
Step-by-step explanation:
Answer:
(x + 3)^2 + (y - 2)^2 = 9
Step-by-step explanation:
<u>Equation for a circle: (x – h)^2 + (y – k)^2 = r^2</u>
<u />
<u>Step 1: Determine what h, k, and r are</u>
<em>h is the x value of the point: -3</em>
<em>k is the y value of the point: 2</em>
<em>r is the radius of the circle: 3</em>
<u>Step 2: Plug in and solve</u>
(x – h)^2 + (y – k)^2 = r^2
(x – (-3))^2 + (y – (2))^2 = (3)^2
<em>(x + 3)^2 + (y - 2)^2 = 9</em>
<em />
Answer: (x + 3)^2 + (y - 2)^2 = 9
A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5
Answer:
4096.50, 4,096.50, $4,096.50, or $4096.5
Step-by-step explanation:
