Can anyone give a Thrall explain ERATOSTHENES’ SIEVE
1 answer:
Answer:
See below
Step-by-step explanation:
The sieve of Eratosthenes is a stepwise method for finding all prime numbers up to a given number n.
Assume that you want to find all the prime numbers between 1 and 100.
Step 1.
Create a square grid with numbers from 1 to 100.
You will be finding numbers in the grid that are composite (not prime) and discarding them. The remaining numbers are the primes.
Step 2.
<em>Mark 1</em>, because it is not a prime.
Step 3.
2 is prime. Mark all <em>multiples of 2</em>, starting from 4 (green in the image below).
Step 4.
3 is prime. Mark all <em>multiples of 3</em>, starting from 9 (blue)
Step 5.
4 is composite, so, <em>mark all multiples of 5</em>, starting from 25 (orange).
Step 6.
6 is composite, so, <em>mark all multiples of 7</em>, starting from 49 (purple).
Step 7.
8, 9, and 10 are composite, and 11² > 100, so we can <em>stop</em>.
All the unmarked numbers are the prime numbers between 1 and 100:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
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Answer:
0.35% of students from this school earn scores that satisfy the admission requirement.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.
This means that
The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?
The proportion is 1 subtracted by the pvalue of Z when X = 2294. So
has a pvalue of 0.9965
1 - 0.9965 = 0.0035
0.0035*100% = 0.35%
0.35% of students from this school earn scores that satisfy the admission requirement.