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2 years ago

Complete the definition.

Mathematics

1 answer:

Sati [7]2 years ago

5 0

Answer:

A relation has an input value which corresponds to an output value. When each input value has one and only one output value, that relation is a function. Functions can be written as ordered pairs, tables, or graphs. The set of input values is called the domain, and the set of output values is called the range.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

The function that represents bruce’s elevation in feet over time in hours is an exponential function that starts at 1,505 feet.

Strike441 [17]

Answer:

<h3>The function for Bruce’s elevation is $f(x)=1505(6)^x$ and because b=6 that is greater than 0, it is an exponential growth function.</h3>

Step-by-step explanation:

We are given initial Bruce’s elevation = 1,505 feet.

Each successive hour, his average elevation change for the hike becomes 6 times the previous hourly elevation change.

We know, the exponential function $f(x)=a(b)^x$ , where a is the initial value, b is the growth factor and x is the exponent represents time in hours.

Therefore, initial value a=1505, growth factor b for exponential function $f(x)=a(b)^x$ is 6.

Plugging a=1505 and b=6 in $f(x)=a(b)^x$ , we get

$f(x)=1505(6)^x$

Also note, if b>0, it would be an exponential growth function.

<h3>Therefore, the function for Bruce’s elevation is $f(x)=1505(6)^x$ and because b=6 that is greater than 0, it is an exponential growth function.</h3>

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3 years ago

Help me please :((: thank u

I am Lyosha [343]

Hey there!

In order for you to find the one that is equivalent to the given expression is to COMBINE YOUR LIKE TERMS then work from there!

12q + q^2 - 8 + q = ?

(q^2) + (12q + q) + (-8)

q^2 = q^2 since it doesn't have any like term(s)

12q + q = 12q + 1q = 13q

-8 = -8 since it doesn't have any like term(s)

Put all the numbers we solved for in An equation and Thats your answer!

If you did it correctly you should have: q^2 + 13q - 8

Answer: q^2 + 13q - 8 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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2 years ago