What is the standard form of 65

Each batch of cookie mix need 0.4 cups of sugar, and each batch can make 16 cookies. If Ashley is making 4 batches of cookies, h

Nady [450]

Answer:

1.6 cups of sugar

Step-by-step explanation:

0.4 cups of sugar for 1 batch of cookies

And to find out the amount of sugar we need

We multiply 0.4 for the amount of batches

In this case it will be

0.4 x 4= 1.6 cups of sugar

4 0

1 year ago

what is the answer to the multiplication problem. Jhon has 20 fish if he lets 6 fish go how many fish dose Jhon have?

spayn [35]

Isn't this a subtraction problem, not a multiplication problem?

If John starts out with 20 fish and lets 6 go, he still has (20-6), or 14, fish.

6 0

2 years ago

Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa

xxMikexx [17]

Answer:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins. Yes No Total

Small 32 18 50

Medium 68 7 75

Large 89 11 100

_____________________________________

Total 189 36 225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1: NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{50*189}{225}=42$

$E_{2} =\frac{50*36}{225}=8$

$E_{3} =\frac{75*189}{225}=63$

$E_{4} =\frac{75*36}{225}=12$

$E_{5} =\frac{100*189}{225}=84$

$E_{6} =\frac{100*36}{225}=16$

And the expected values are given by:

Size Company/ Heal. Ins. Yes No Total

Small 42 8 50

Medium 63 12 75

Large 84 16 100

_____________________________________

Total 189 36 225

And now we can calculate the statistic:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0

3 years ago

the big wheel could have a 52 inch diameter and the small wheel could have an 18 inch diameter.What is the circumference of the

BlackZzzverrR [31]

Before we begin, let's cross out "the small wheel could have an 18 inch diameter". This is useless information and should be disregarded to avoid confusion. Lots of questions include extraneous information to make you second guess yourself, so it is important to be aware of what the question is asking you and what you need in order to answer it.

The formula for circumference is $\pi$ x diameter. With this formula, we can substitute the value of the diameter, 52, into the equation.

Circumference = 3.14 x 52
Circumference = 163.28

Final Answer: the circumference of the big wheel is 163.28 inches
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8 0

2 years ago

Janelle has taken an online defensive safety driving course and is now completing the course exam. While taking the exam on the

LenKa [72]

There are 70 questions on the test

5 0

2 years ago