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1 year ago

Can someone help me out please ?

Mathematics

1 answer:

allsm [11]1 year ago

3 0

Answer:

$8 + x = 25 \\ x = 25 - 8 \\ 17$

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use the table to find each ratio 8 white socks and 6 black socks and 4 blue socks and 5 brown socks ... white socks to brown soc

nevsk [136]

<h3>Answer:</h3>

white : brown = 8 : 5
black : total = 6 : 23

<h3>Explanation:</h3>

Each of the ratio components (white socks, brown socks, black socks, total socks) has an associated number (8, 5, 6, 23). Write the desired ratio using the associated numbers.

8 0

2 years ago

Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.

Aloiza [94]

Answer:

0.70275

Step-by-step explanation:

Data provided in the question:

4e²ˣ⁻¹ -1 = 5

now solving for 'x'

⇒ 4e²ˣ⁻¹ = 5 + 1

⇒ 4e²ˣ⁻¹ = 6

⇒ $e^{(2x-1)} =\frac{6}{4}$

⇒ $e^{(2x-1)} =\frac{3}{2}$

now,

taking natural log both sides, we get

⇒ 2x - 1 = $\ln(\frac{3}{2})$

also,

we know

⇒ $\log(\frac{A}{B}) = \log(A)+\log(B)$

thus,

⇒ 2x - 1 = ln(3) - ln(2)

⇒ 2x - 1 = 1.0986 - 0.6931

⇒ 2x - 1 = 0.4055

⇒ 2x = 0.4055 + 1

⇒ 2x = 1.4055

⇒ x = 0.70275

3 0

3 years ago

Write an equation of the line that passes through each points (5,6) (3.4)

ioda

Answer:

$y = x + 1$ .

Step-by-step explanation:

Start by finding the slope of this line.

If a slanting line goes through $(x_{0},\, y_{0})$ and $(x_{1},\, y_{1})$ , where $x_{0} \ne x_{1}$ , the slope of this line would be:

$\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}}\end{aligned}$ .

The line in this question goes through $(5,\, 6)$ and $(3,\, 4)$ . Hence, the slope of this line would be:

$\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}} \\ &= \frac{6 - 4}{5 - 3} \\ &= 1\end{aligned}$ .

If a slanting line with a slope of $m$ and goes through the point $(x_{0},\, y_{0})$ , the equation of this line in the point-slope form would be:

$y - y_{0} = m,\, (x - x_{0})$ .

For the line in this question, the slope is $m = 1$ . Take $(5,\, 6)$ as the chosen point on this line. The point-slope form equation of this line would be: