To solve for this, we need to figure out the sum of any two numbers on the dice that will become a pair factor for the listed answers.
What I mean by that is that we need to find the probability between how many two numbers will sum up to the answer.
3 can be 1 + 2, that's it. 3 has a probability of (1).
4 has a sum of 1 + 3, and 2 + 2, that's it. 4 has a probability of (2).
7 has a sum of 1 + 6, 2 + 5, and 3 + 4. 7 has a probability of (3).
11 has a sum of 5 + 6, that's it. 11 has a probability of (1).
The numbers in parenthesis are the probabilities.
7 has the highest number, so 7 has the highest probability.
Your answer is: 7.
I hope this helps!
It’s solved by using the cosine rule
The length of the rectangle is = 72 cm
The width of the rectangle is = 56 cm
Area of the rectangle is = 
= 
cm²
As given, the other rectangle has the same area as this one, but its width is 21 cm.
Let the length here be = x
Hence, length is 192 cm.
We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.
So, in the new rectangle,constant of variation=k is given by,
or 
Hence, the constant of variation is 
Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2
