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konstantin123 [22]
3 years ago
6

In ΔVWX, the measure of ∠X=90°, XW = 24, WV = 25, and VX = 7. What ratio represents the tangent of ∠W?

Mathematics
1 answer:
Paha777 [63]3 years ago
5 0

Answer: tan W= opposite/adjacent = 7/24

Step-by-step explanation:

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72

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Which equation has the same solution as x<br> 2<br> −<br> 6<br> x<br> −<br> 14<br> =<br> 0
Slav-nsk [51]

Answer:

x = -2

Step-by-step explanation:

6 0
3 years ago
There are 172 South American animals in the Springdale zoo. That is 45 more than half the number of african animals in the zoo.
patriot [66]
N=number of African animals in the zoo;
we suggest this equation:
172=45+n/2
Least common multiple=2
172*2=45*2+n
344=90+n
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Answer: there are 254 African animals in the zoo.
6 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
6x-5y=15. X=y+3. X= ?y=?
sukhopar [10]

Answer:

x=0

y=-3

6x-5y=15

x=y+3

Replace x with y+3

6(y+3)-5y=15

Distribute

6y+18-5y=15

y= -3

x=0

4 0
3 years ago
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