Angles PQT and RQS are vertical angles and angles PQR and TQS are vertical angles.
angle PQS and TQR are straight angles
angles TQP and PQR form a linear pair. they are also adjacent by default. the other angles have these same features.
that should bout do it. hope it helped!
108 = ( x)(48-x)
108 = 48x - x^2
48x -x^2 -108 = 0
I'm assuming you're doing solve the square right now, so you should be able to do the rest.
Answer:
ok
Step-by-step explanation:
That would be A, its the only on where all the dots line with the numbers given
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
