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2 years ago

I need help solving this can you help me?

Mathematics

2 answers:

qwelly [4]2 years ago

6 0

Hey girlie can see the question

nordsb [41]2 years ago

5 0

Can you send a clearer pic?

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Which points lie in Quadrant III? Choose all answers that are correct. A (–8, –2) B(–5, 4) C(–3, –9) D (4, –1) E (7, 0)

Studentka2010 [4]

Quadrant 3 will have a negative x and a negative y........so ur answers are :
A and C

4 0

3 years ago

Read 2 more answers

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

6 0

2 years ago

Read 2 more answers

I need to find the product of f and g. what is the domain and range of the product

velikii [3]

Step-by-step explanation:

Putting both functions into a graphing calculator, we can easily find the domain and range. (attatched)

By looking at the graph, we can tell that f(x) is a quadratic function because of the symmetry. We can also tell that it never goes below 4. Knowing this, we can determine the domain and range.

Domain: {x | all real numbers}

Range: {y | y > 4}

By looking at the graph, we can tell that g(x) is an exponential function because it has a curve, and never goes below the x. Knowing this, we can determine the domain and range.

Domain: {x | all real numbers}

Range: {y | y > 0}