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2 years ago

Which equation(s) represents proportional relationship(s) with a constant of proportionality equal to 2?

Mathematics

1 answer:

In-s [12.5K]2 years ago

6 0

Answer:

y=2x

Step-by-step explanation:

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Factorize -pq -pr +mq +mr

trapecia [35]

Answer:

(q + r) (m - p)

Explanation:

-pq - pr + mq + mr

Factor out common term 'p'

= -p(q + r) + mq + mr

Factor out common term 'm'

= -p(q + r) + m(q + r)

Factor out common term '(q + r)'

= (q + r) (-p + m)

(q + r) (m - p)

- PNW

5 0

2 years ago

Salma received 7/9 of the 81 votes cast for class president. How many votes did she receive?

Ivanshal [37]

Answer: 63 votes

Step-by-step explanation:

Simply multiply 81 by 7/9 to get the answer, 63 votes.

Hope it helps :) and let me know if you want me to elaborate.

6 0

2 years ago

Read 2 more answers

Jessica opened a bank account that earns 2 percent interest compounded annually. Her initial deposit was $100, and she uses the

klasskru [66]

Answer:

x = 1.02.

Step-by-step explanation:

The x is a factor worked out from the annual interest written as a decimal fraction.

So we have 2% = 2/100 = 0.02.

The amount at the end of the first year is $100 + 0.02*100

= $100* 1.02, and in the second year it will be $100* 1.02^t where t = 2 and so on.

So we see that x in the given expression is 1.02.

5 0

3 years ago

What is <br>1.63 x 0.98 =

yarga [219]

Answer:

1.5974

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one

d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0

3 years ago