.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 ) ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
-2a =38
a = -19
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0 .... b = 15
the center is :w(-19,15)
13.41 is 13.406 rounded to nearest hundreth
If you were to list these numbers in order from greatest to least, it would be 1.29, 1.202, 1.02.
Hope this helps!!
Answer:
5×10⁻²
Step-by-step explanation:
- Move the decimal so there is one non-zero digit to the left of the decimal point.
- The number of decimal places you move will be the exponent on the 10. a. If the decimal is being moved to the right, the exponent will be negative.
b. If the decimal is being moved to the left, the exponent will be positive.
- Therefore. The answer is 5×10⁻²
The new point would then be at (1, -10)
