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3 years ago

What is the value of 4³ ? 12 16 43 64

Mathematics

2 answers:

masha68 [24]3 years ago

7 0

64
4 x 4 x 4 = 64
hope this helps x

anzhelika [568]3 years ago

3 0

Answer:

Step-by-step explanation:

$4^{3}$ = 4 × 4 × 4
4 × 4 × 4 = 64

I hope this helps!

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I need help with this question

Black_prince [1.1K]

Answer:

Step-by-step explanation:

The slope-intercept form is found by solving that equation for y.

If $y-3=\frac{1}{2}(x-1)$ then

$y-3=\frac{1}{2}x-\frac{1}{2}$ and

$y=\frac{1}{2}x-\frac{1}{2}+3$ and

$y=\frac{1}{2}x-\frac{1}{2}+\frac{6}{2}$ so

$y=\frac{1}{2}x+\frac{5}{2}$

The answer you have chosen is the correct one! Good job!

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3 years ago

Juan's pit crew was able to get his car back onto the racetrack 0.4 seconds faster than Paul's crew. Paul's crew took 1.3 second

9966 [12]

Answer:

6.7 seconds

Step-by-step explanation:

Juan= Paul-0.4

Paul=Terry+1.3

We can substitute Terry+1.3 for Paul since they are equal

juan=(Terry-0.4)+1.3

terry=5.8

juan=(5.8-0.4)+1.3

juan=6.7

4 0

3 years ago

A bag contains 2 oranges, 3 grapefruits, and 1 tangerine. A piece of fruit is chosen from the bag at random. What is the probabi

Lesechka [4]

Answer:

50%

Step-by-step explanation:

The probability of picking a grapefruit is the amount of grapefruits over the amount of total fruit. There are 3 grapefruits, and 6 total pieces of fruit. 3/6 is equal to 1/2, so the probability is 1/2 or 0.5 or 50%.

3 0

4 years ago

Read 2 more answers

Data collected over time on the utilization of a computer core (as a proportion of the total capacity) were found to possess a r

Marianna [84]

Answer:

The probability that the proportion of the core being used at any particular time will be less than 0.10 is 0.08146

Step-by-step explanation:

$\mu =\frac{\alpha }{\alpha +\beta } = \frac{1}{1 + \frac{\beta}{\alpha} }$ 1/3 0.33 = 33.33 %

The Probability of that the proportion of the core being used at any particular time will be less than 0.10 is given by

PDF = $\frac{x^{\alpha -1} (1-x)^{\beta -1} }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$

where x = 0.1

α = 2 and β = 4

PDF = $\frac{0.0729 }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 1.458

CDF = $\frac{\int\limits^{0.1}_0 {t^{\alpha -1} (1-t)^{\beta -1}} \, du }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 0.08146

The probability that the proportion of the core being used at any particular time will be less than 0.10 = 0.08146.

3 0

3 years ago

Solve for t <br> 1000=(10000)/(5+1245(e^-.97t))

vladimir2022 [97]

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6 0

2 years ago