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Katen [24]
2 years ago
10

What is the value of 4³ ? 12 16 43 64

Mathematics
2 answers:
masha68 [24]2 years ago
7 0
64
4 x 4 x 4 = 64
hope this helps x
anzhelika [568]2 years ago
3 0

Answer:

64

Step-by-step explanation:

  1. 4^{3} = 4 × 4 × 4
  2. 4 × 4 × 4 = 64

I hope this helps!

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What is the equation of this line?<br> Please Help <br><br> Y=4x<br> Y=-1/4x<br> Y=-4x<br> Y=1/4x
Sveta_85 [38]

Answer: Y=-1/4x

Step-by-step explanation:

A good way to find an equation of a line is to look for the slope. An obvious spot on this line would be when it crosses (0,0), and another one to the right would be when it crosses at (4,-1).

The slope is rise over run, or if we use the two points we found, "rise" would be -1, because it's dropping 1 unit when going from (0,0) to (4,-1), and the "run" would be 4, because it moves to the right 4 from (0,0) to (4,-1).

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Out of all the equations we're given, we can look for the one with a slope of -1/4, which is given to us:

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7 0
3 years ago
What are the approximate solutions of 2x^2 + x = 14, rounded to the nearest hundredth?
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Hello,

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or x=(-1+√113)/4=2,40753≈2.41


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Jack has two square based pyramids that are the same size.he stick the square faces togather to make a new 3-d shape.how many fa
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3 years ago
The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than av
34kurt

Answer:

Probability that the 50 randomly selected laptops will have a mean replacement time of 3.1 years or less is 0.0092.

Yes. The probability of this data is unlikely to have occurred by chance alone.

Step-by-step explanation:

We are given that the replacement times for the model laptop of concern are normally distributed with a mean of 3.3 years and a standard deviation of 0.6 years.

He then randomly selects records on 50 laptops sold in the past and finds that the mean replacement time is 3.1 years.

<em>Let M = sample mean replacement time</em>

The z-score probability distribution for sample mean is given by;

            Z = \frac{ M-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean replacement time = 3.3 years

            \sigma = standard deviation = 0.6 years

            n = sample of laptops = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the 50 randomly selected laptops will have a mean replacement time of 3.1 years or less is given by = P(M \leq 3.1 years)

 P(M \leq 3.1 years) = P( \frac{ M-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 3.1-3.3}{\frac{0.6}{\sqrt{50} } }} } ) = P(Z \leq -2.357) = 1 - P(Z \leq 2.357)

                                                           = 1 - 0.99078 = <u>0.0092</u>  or  0.92%          

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.357 in the z table which will lie between x = 2.35 and x = 2.36 which has an area of 0.99078.</em>

Hence, the required probability is 0.0092 or 0.92%.

Now, based on the result above; <u>Yes, the computer store has been given laptops of lower than average quality</u> because the probability of this data is unlikely to have occurred by chance alone as the probability of happening the given event is very low as 0.92%.

8 0
3 years ago
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