The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
x=3; y=3
Step-by-step explanation:
y = -1/2 x + 9/2
so if we multiply by 2 on both sides
2y = -x + 9
and we know that y = 3x-6
so we get
2(3x-6)=-x+9
6x-12 = - x + 9
7x = 21
x = 3
y = 3 * 3 - 6
y=3
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x=3, y=3
You put them in the equation and they should work.
=D
Answer:
f?dd,dyuduxccucucucucucuccc
Solutions
Factor <span>8x</span>²<span>−27
</span><span>=<span>8x</span></span>²<span>−<span>27
You can not factor </span></span><span>8<span>x</span></span>²−<span>27</span>
Answer:
.
Step-by-step explanation:
