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faltersainse [42]
3 years ago
10

CAN is bisected by AP. If m CAN = 52°, find m CAP and m PAN. A. M CAP = 26°, m PAN = 26° B. M CAP = 52°, m PAN = 52° C. M CAP =

26°, m PAN = 52° D. M CAP = 52°, m PAN = 26
Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

  A. M CAP = 26°, m PAN = 26°

Step-by-step explanation:

The angle bisector divides the original angle into two angles, each with half the measure of the original. (It can help to draw a diagram.) Half of 52° is 26°, so each of the created angles have that measure.

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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
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Answer:

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Step-by-step explanation:

Given

<u>Pyramid A</u>

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<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

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Where s represents the side lengths

First, we calculate the height of pyramid A

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V = \frac{1}{3} * B * h

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Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

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V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

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B = \frac{1}{2} * 6^2 * sin(60)

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Where

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V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

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