We have been given a system of equations and we are asked to write correct coefficient matrix for this system.
Since we know that a matrix for a system of equations is in the form: 
, where A represents the coefficient matrix, X is variables''s matrix and B is the constant matrix.
We are given two equation and two unknown variables, so our coefficient matrix will be a 
matrix. Our matrices for variable and constant will be of dimensions 
(column matrix).
We can represent our given system of equations in matrix form as:
![\left[\begin{array}{ccc}3&4\\-1&-6\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right]= \left[\begin{array}{ccc}12\\10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%264%5C%5C-1%26-6%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
Now let us find our A, X and B parts from above matrices.
![A=\left[\begin{array}{ccc}3&4\\-1&-6\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%264%5C%5C-1%26-6%5Cend%7Barray%7D%5Cright%5D)
![X=\left[\begin{array}{ccc}x\\y\end{array}\right]](https://tex.z-dn.net/?f=X%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D)
![B=\left[\begin{array}{ccc}12\\10\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
Since we know that A represents coefficient matrix, therefore, correct coefficient matrix for our system of equations will be,
![\left[\begin{array}{ccc}3&4\\-1&-6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%264%5C%5C-1%26-6%5Cend%7Barray%7D%5Cright%5D)
Answer:
tell me if i need to resend it
Step-by-step explanation:
Well since 27% in decimal form is .27, that mean .48 is greater.
27% < 0.48
905=5a
905/5=5a/5
181=a
HOPE THIS HELPS!!!!!!!!!!
The length of the rectangle is = 72 cm
The width of the rectangle is = 56 cm
Area of the rectangle is = 
= 
cm²
As given, the other rectangle has the same area as this one, but its width is 21 cm.
Let the length here be = x
Hence, length is 192 cm.
We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.
So, in the new rectangle,constant of variation=k is given by,
or 
Hence, the constant of variation is 
