I really need this answer please help

Mathematics

1 answer:

iren2701 [21]2 years ago

5 0

I’m not completely sure but I think the answer is C.

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Sellus

igor_vitrenko [27]

Answer:

3.9

Step-by-step explanation:

Given the data:

Payout ($) (x) : 0 2 4 8 10

Probability p(x) : 0.35 0.2 0.1 0.2 0.15

The expected winning ; E(X) = Σ(x * p(x))

Σ(x * p(x)) = (0*0.35)+(2*0.2)+(4*0.1)+(8*0.2)+(10*0.15)

= 0 + 0.4 + 0.4 + 1.6 + 1.5

= 3.9

8 0

2 years ago

Point B lies between A and C. If AB = 15 units and AC = 50 units, what is the length of BC?

Alexxandr [17]

Answer:

BC = 35 units

Step-by-step explanation:

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5 0

3 years ago

The number of acres a farmer uses for planting pumpkins will be at least 2 times the number of acres for planting corn. The diff

jeka94

Answer:

Step-by-step explanation:

A) Let x represent acres of pumpkins, and y represent acres of corn. Here are the constraints:

x ≥ 2y . . . . . pumpkin acres are at least twice corn acres

x - y ≤ 10 . . . . the difference in acreage will not exceed 10

12 ≤ x ≤ 18 . . . . pumpkin acres will be between 12 and 18

0 ≤ y . . . . . the number of corn acres is non-negative

B) If we assume the objective is to maximize profit, the profit function we want to maximize is ...

P = 360x +225y

C) see below for a graph

D) The profit for an acre of pumpkins is the highest, so the farmer should maximize that acreage. The constraint on the number of acres of pumpkins comes from the requirement that it not exceed 18 acres. Then additional profit is maximized by maximizing acres of corn, which can be at most half the number of acres of pumpkins, hence 9 acres.

So profit is maximized for 18 acres of pumpkins and 9 acres of corn.

Maximum profit is $360·18 +$225·9 = $8505.