Help please and thank
2 answers:
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Answer:
<u>First question answer:</u> The limit is 69
<u>Second question answer:</u> The limit is 5
Step-by-step explanation:
For the first limit, plug in in the expression
, that's the answer for linear equations and limits.
So we have:
The answer is 69
For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value into the simplified expression to get the correct answer. Shown below:
<em>Now putting 1 in gives us the limit:</em>
So the answer is 5
Answer:
Step-by-step explanation:
= - 4 - 2( - 3) = 2
= - 4 - 2( - 2) = 0
= - 4 - 2( - 1) = - 2
= - 4 - 2( 0 ) = - 4
= - 4 - 2( 1 ) = - 6
Range: { 2, 0, - 2, - 4, - 6 }
The perimeter of a shape is the sum of its side lengths.
<em>Joshua miscalculated the third length of the triangle</em>
First, we calculate the third length (x) of the triangle.
Because the triangle is right-angled, we can make use of Pythagoras.
So we have:
Take square roots of both sides
The other shape in the figure is a square.
So, the perimeter (P) is
---- i.e. the sum of the visible lengths
So, we have:
Evaluate like terms:
Hence, Joshua's error is that:
<em>He miscalculated the third length of the triangle</em>
Read more about perimeters at: