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inna [77]
3 years ago
7

Find the exact length of the third side 7 3

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

8

Step-by-step explanation:

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PLEASE HELP FOR BRAINLIEST
aliina [53]

For the first pic:

S= (3,4)

U= (-4,0)

V= (1,-2)

T= (-2,-3.5)

I hope this helped! Sorry if you get this wrong! :)

6 0
4 years ago
In a figure, m<1=m<2. Which property can be used to reason that m<2=m<1.
Aneli [31]

Answer: Symmetric property of equality

This is the idea that if x = y, then y = x. We can swap the left and right sides of an equation, and still mean the same thing. The same applies to congruences as well.

5 0
3 years ago
The ratio of boys to girls in Mr. Baker’s social studies class is 2 to 3. If there are 30 total students in the class, how many
nadya68 [22]
A.6 the answer are A.6

4 0
3 years ago
Read 2 more answers
Records indicate that x years after 2008, the average property tax on a three bedroom home in a certain community was T(x) =20x^
dem82 [27]

Answer:

a) 40 dollars

b) 480 dollars

Step-by-step explanation:

Given the average property tax on a three bedroom home in a certain community modelled by the equation T(x) =20x²+40x+600, the rate at which the property tax is increasing with respect to time in 2008 can be derived by solving for the function T'(x) at x=0

T'(x) = 2(20)x¹ + 40x° + 0

T'(x) = 40x+40

At x = 0,

T'(0) = 40(0)+40

T'(0) = 40

Hence the property tax was increasing at a rate of 40dollars with respect to the initial year (2008).

b) There are 4 years between 2008 and 2012. To know how much that the tax change between the years 2008 and 2012, we will find T(4) - T(0)

Given T(x) =20x²+40x+600

T(4) =20(4)²+40(4)+600

T(4) = 320+160+600

T(4) = 1080 dollars

Also T(0) =20(0)²+40(0)+600

T(0) = 0+0+600

T(0)= 600 dollars

T(4) - T(0) = 1080 - 600

T(4) - T(0) = 480 dollars

Hence, the tax has changed by $480 between 2008 and 2012

6 0
4 years ago
Arrange the summation expressions in increasing order of their values.
nalin [4]
We'll solve for each one of them:

\sum_{i=1}^{4}4(5)^{i-1} = (4(5)^{1-1}) + (4(5)^{2-1}) + (4(5)^{3-1}) + (4(5)^{4-1})
=4+20+100+500 = 624

\sum_{i=1}^{5}3(4)^{i-1} = (3(4)^{1-1}) + (3(4)^{2-1}) + (3(4)^{3-1}) + (3(4)^{4-1}) + (3(4)^{5-1})
=3+12+48+192+768=1023

\sum_{i=1}^{2}5(6)^{i-1} = (5(6)^{1-1}) + (5(6)^{2-1})
=5+30=35

\sum_{i=1}^{4}5^{i-1} = (5^{1-1})+(5^{2-1})+(5^{3-1})+(5^{4-1})
=1 + 5+ 25+125 = 156

So, our totals are: 624, 1023, 35, and 156. So clearly, 1023 > 624 > 156 > 35. W can write it as (your answer):

\sum_{i=1}^{2}5(6)^{i-1}

Hope this helps! If anything is confusing, you can always DM me.
3 0
3 years ago
Read 2 more answers
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