Answer: 0.42 mg
Step-by-step explanation:
Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.
Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl =
Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-
Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg
Answer:
−19810916
Step-by-step explanation:
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Answer:
Step-by-step explanation:
C