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3 years ago

Plzz help with this question

Mathematics

2 answers:

alexandr402 [8]3 years ago

7 0

Answer:

rip Pop we aint neva gettin cool with the opps

190000

hope this helps

Step-by-step explanation:

Reika [66]3 years ago

7 0

1230 is the answer to the question

You might be interested in

UkoKoshka [18]

Answer:

-8n + 9

Step-by-step explanation:

Given that,

A = -3n + 2

B = 5n - 7

Before solving you have to know that,

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

( + ) × ( - ) = ( - )

Let us solve now.

A - B

-3n + 2 -(5n - 7)

-3n + 2 - 5n + 7

Combine like terms

-3n - 5n + 2 + 7

-8n + 9

Hope this helps you.

Let me know if you have any other questions :-)

5 0

2 years ago

Su Ling started an art project with 1 yard felt. She used 5/6 yard. How much felt does Su Ling have left?

Vadim26 [7]

Su has about 1/6 yards of felt left my dude/dudett

7 0

4 years ago

Read 2 more answers

6/9 is a rational number. Select all the rational numbers that are equivalent to .

Marianna [84]

Option b) and c) is correct, i.e. 2/3 and 0.66(line over 66)7

6/9 is a rational number.
similar ration number can be given as -

<h3>What is rational number?</h3>

Rational numbers are the numbers that can be structured in the form of the fraction of integers. Eg- 5/6, 2/3 etc.

From the option, by above definition 2/3, 0.66(line over 66)7 seems to be an equivalent rational numbers because
6/9=2/3= 0.66(line over 66)7.

Thus, Rational numbers 2/3, 0.66(line over 66)7 are equivalent to 6/9.

Learn more about Rational numbers here:
brainly.com/question/17450097

#SPJ1

5 0

2 years ago

Express the complex number in trigonometric form -6 + 6sqrt3i

marusya05 [52]

$\large\begin{array}{l}\\\\ \textsf{This is a complex number in }\mathsf{a+bi}\textsf{ form:}\\\\ \mathsf{z=-6+6\sqrt{3}\,i}\\\\ \textsf{where }\mathsf{a=-6~~and~~b=6\sqrt{3}.} \end{array}$

$\large\begin{array}{l}\\\\ \bullet~~\textsf{1}\mathsf{^{st}}\textsf{ step: Find the absolute value of z (complex modulus of z):}\\\\ \mathsf{|z|=\sqrt{a^2+b^2}}\\\\ \mathsf{|z|=\sqrt{(-6)^2+(6\sqrt{3})^2}}\\\\ \mathsf{|z|=\sqrt{36+36\cdot 3}}\\\\ \mathsf{|z|=\sqrt{36\cdot 108}}\\\\ \mathsf{|z|=\sqrt{144}}\\\\ \mathsf{|z|=12} \end{array}$

$\large\begin{array}{l}\bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Find the argument }\mathsf{\theta}\textsf{ of z:}\\\\ \mathsf{arg(z)=\theta}\\\\ \textsf{is an angle that satisfies the following conditions:}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{a}{|z|}=\dfrac{a}{\sqrt{a^2+b^2}}}\\\\ \mathsf{sin\,\theta=\dfrac{b}{|z|}=\dfrac{b}{\sqrt{a^2+b^2}}} \end{cases}\qquad\quad-\pi$

$\large\begin{array}{l}\textsf{For }\mathsf{z=-6+6\sqrt{3}\,i,}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{-6}{12}=-\,\dfrac{1}{2}}\\\\ \mathsf{sin\,\theta=\dfrac{6\sqrt{3}}{12}=\dfrac{\sqrt{3}}{2}} \end{cases}\\\\\\ \textsf{Since}\\\\ \mathsf{cos\,\theta0,}\\\\ \theta\textsf{ lies in the 2}\mathsf{^{nd}}\textsf{ quadrant.}\\\\\\\textsf{Therefore,}\\\\ \mathsf{\theta=\dfrac{2\pi}{3}~rad~~(120^\circ)} \end{array}$

$\large\begin{array}{l}\bullet~~\textsf{3}\mathsf{^{rd}}\textsf{ step: Express z in the trigonometric form:}\\\\ \begin{array}{rcl} \mathsf{z}&\!\!=\!\!&\mathsf{|z|\cdot (cos\,\theta+i\,sin\,\theta)}\\\\ \mathsf{-6+6\sqrt{3}\,i}&\!\!=\!\!&\mathsf{12\cdot \left(cos\, \dfrac{2\pi}{3}+i\,sin\,\dfrac{2\pi}{3}\right)\qquad\quad\checkmark} \end{array} \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154167

$\large\textsf{I hope it helps.}$

Tags: <em>complex number trigonometric form trig absolute value modulus argument angle</em>

4 0

3 years ago

X+2=12<br><br> Please take my points

Pavel [41]

X + 2 = 12
subtract both sides by 2
x = 10

3 0

3 years ago

Read 2 more answers