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velikii [3]
3 years ago
7

A Genesse High School, the Sophomore class has 60 more students than the Freshmen class. The junior class has 50 fewer students

than twice the students than twice the students in the Freshmen class. The senior class is three times as large as the freshmen class. If there are a total of 1,427 students at Genesse High School how many students are in the Freshmen class?
Mathematics
1 answer:
alexira [117]3 years ago
3 0
1427 = (F) (+ F + 60) (2F - 50) (+ 3F)
<em>Each pair of brackets represents one of the classes - F meaning Freshmen Class. It has been split into brackets for demonstrational purposes - nothing is being multiplied.</em>
F is an unknown number and each other class size is based off of that so we put it in algebraic terms in order to work it out.
1 - Freshmen Class
2 - Sophomore Class (Freshmen Class + 60 more students)
3 - Junior Class ( Twice the size of the Freshmen Class - 50 students)
4 - Senior Class (Three times the size of the Freshmen Class)

All this can be simplified to 7F + 10 = 1427
1427 - 10 = 1417
1417/7 = 202.428....

Is there a mistake in the question?

Following the question with 202 as the answer - the number 1424 is reached
If increased to 203 - 1431 is reached.
The answer shouldn't include half a person.

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Answer:

The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550    (1)

Also, since we have fifteen more​ $10 bills than​ $50 bills, n₁ = n₃ + 15  (2)

and we have 4 more than three times as many​ $20 bills as​ $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

10(n₃ + 15) + 20n₂ + 50n₃ = 1550

expanding the bracket, we have

10n₃ + 150 + 20n₂ + 50n₃ = 1550

collecting like terms, we have

60n₃ + 150 + 20n₂ = 1550

inserting equation (3), we have

60(3n₂ + 4) + 150 + 20n₂ = 1550

expanding the bracket, we have

180n₂ + 240 + 150 + 20n₂ = 1550

collecting like terms, we have

200n₂ + 390 = 1550

subtracting 390 from both sides, we have

200n₂ = 1550 - 390

200n₂ = 1160

dividing both sides by 200, we have

n₂ = 1160/200

n₂ = 5.8

n₂ ≅ 6 since it cannot be a fraction.

Substituting this into (3), we have

n₃ = 3n₂ + 4 = 3(6) + 4 = 18 + 4 = 22

substituting n₃ into (2), we have

n₁ = n₃ + 15 = 22 + 15 = 37

So, the number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

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Solve his problem for X and Y​
Verizon [17]

<em><u>Answer:</u></em>

<em><u>y = 5, 3; x = 171, 155</u></em>

<em><u>Step-by-step explanation:</u></em>

8y - 15 = y^2

y^2-8y+15=0

y^2-3y-5y+15=0

y(y-3)-5(y-3)=0

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Answer:

The correct option is B.

Step-by-step explanation:

The given expression is

\sqrt{144x^{36}}

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\sqrt{ab}=\sqrt{a}\sqrt{b}

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Use the property of exponent.

a^{mn}=(a^m)^n

\sqrt{144x^{36}}=12\times \sqrt{(x^{18})^2}

\sqrt{144x^{36}}=12\times x^{18}

\sqrt{144x^{36}}=12x^{18}

Therefore option B is correct.

3 0
3 years ago
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