Answer:
Options A, B, and C are all possible.
Explanation:
We know that the instantaneous velocity of the dog at 3:14PM is possitive to toward the flowers. But what about the acceleration to toward the flowers?
If the dog is decreasing speed at 3:14PM, it means that acceleration is negative toward the flowers, hence (since F=ma) the net force points away from the flowers.
If the dog is increasing speed at 3:14PM, it means that acceleration is positive toward the flowers, hence (since F=ma) the net force points toward the flowers.
If the dog is not increasing nor decreasing speed at 3:14PM, it means that acceleration is 0, hence (since F=ma) the net force is null and it does not point neighter to toward the flowers nor away from the flowers. This happens when the forces acting on the dog are equal to both sides.
Answer:
113.7
Explanation:
maximum distance (s) = 8.9 km
reference intensity (I0) = 1 x 10^{-12} W/m^{2}
power of a juvenile howler monkey (p) = 63 x 10^{-6} W
distance (r) = 210 m
intensity (I) = power/area
where we assume the area of a sphere due to the uniformity of the output in all directions
area = 4π
= 4π x
= 554,176.9 m^{2}
intensity (I) = ![\frac{63 x 10^{-6} }{554,176.9} = 113.7 x 10^{-12}](https://tex.z-dn.net/?f=%5Cfrac%7B63%20x%2010%5E%7B-6%7D%20%7D%7B554%2C176.9%7D%20%3D%20113.7%20x%2010%5E%7B-12%7D)
therefore the desired ratio I/I0 =
= 113.7
Answer:
0 J
Explanation:
From the diagram below; we would notice that the Force (F) = Tension (T)
Also the angle θ adjacent to the perpendicular line = 90 °
The Workdone W = F. d
W = Fd cos θ
W = Fd cos 90°
W = Fd (0)
W = 0 J
Hence the force is perpendicular to the direction of displacement and the net work done in a circular motion in one complete revolution is = 0
In his celebrated Second Law of Motion, Newton wrote:
Net force = (mass) x (acceleration).
By the process of "plugging in numbers", we can write
1255 N = (41 kg) x (acceleration)
Now, after dividing each side by (41 kg), we have
(1255 N) / (41 kg) = acceleration.
But (1255N)/(41kg) = 30.61 m/s² .
So unless we have carelessly blooped the calculations somewhere,
that 30.61 m/s² is the answer we're looking for.
A pulsar has the strongest magnetic field