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GREYUIT [131]
3 years ago
9

How does the law of conservation of mass apply to this reaction:Al+3HCl-->H2+AlCl3

Physics
1 answer:
Veronika [31]3 years ago
8 0
This reaction is unbalanced. If you balance it, it would be:


2Al + 6HCl --> 3H2 + 2AlCl3

That way there are two aluminums on each side, six hydrogens on each side, and six chlorines on each side.

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What are ferrous and non ferrous metals<br> ​
pogonyaev

Answer:

Ferrous metals are ones that contain iron ( can be alloys of iron), and non-ferrous metals don't contain iron.

Hope this helps, let me know if you have any questions! :)

8 0
2 years ago
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Phosphorus is most abundant in the: a)lithosphere b)atmosphere c)hydrosphere d)cryosphere
kobusy [5.1K]
I would say the atmosphere. 

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6 0
3 years ago
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As the people sing in church, the sound level everywhere inside is 101 dB . No sound is transmitted through the massive walls, b
katovenus [111]

The sound level from 1 km away is 46.4 dB and the sound energy radiated through the windows and doors in 20 min is 332.6 J

<h3>What do you mean by sound radiates?</h3>

Multiple plate modes participate in the forced vibration of a baffled plate that produces sound. The emitted sound power depends on the activation of each plate mode by the external pressures as well as the radiation characteristics of the individual plate modes and their mutual interaction via their radiated sound, as shown in eq (20) and (24). The net contribution of the mutual interaction between plate modes to the overall sound power may be disregarded if a plate is activated in a manner that results in a plate vibration field that can be defined as reverberant with an equal distribution of energy over all modes.

(Lw) = 10·log (W/Wo) dB

Given:

sound level,  \beta= 101 dB

Area, A = 22\;m^{2}

Time, \triangle t = 20\;min=1200\;s

Intensity, I=1\times 10^{-12}\;W/m^{2}

r=1\;km=1000\;m

(a)

We know that, Sound level is,

\beta=10\times log(\frac{I}{I_{o} } )

Solving the above equation for sound intensity,

I=I_{o} \times 10^{\frac{\beta}{10} }

I=1 \times 10^{-12}  \times 10^{\frac{101}{10} }

I=0.0126\;W/m^{2}

Therefore, The sound energy is,

E=P\times \triangle t

Substitute P=I \times A in the above equation,

E=I \times A \times \triangle t

E=0.0126 \times 22 \times 1200

E=332.6\;J

(b)

Half of a sphere area with 1 km radius is equal to Area of the sound at 1 km distance,

A_{hemisphere}  = \frac{1}{2} \times 4 r^{2} \pi

Substitute the known value in the above equation ,

A_{hemisphere} = \frac{1}{2} \times 4 (1000)^{2} \pi

A_{hemisphere} = 6283185\;m^{2}

Sound Intensity is,

I = \frac{P}{A_{hemisphere}}

Substitute P=I \times A in the above equation,

I = \frac{I \times A}{A_{hemisphere}}

Substitute the known value in the above equation,

I = \frac{0.0126 \times 22}{6283185}

I = 4.4 \times 10^{-8}\;W/m^{2}

Sound level is,

\beta=10\times log(\frac{I}{I_{o} } )

Substitute the known value in the above equation,

\beta=10\times log(\frac{4.4 \times 10^{-8} }{1 \times 10^{-12} } )

\beta=46.4\;dB

To learn more about sound radiates, Visit:

brainly.com/question/20360072

#SPJ4

8 0
1 year ago
What is 7.866 rounded to the nearest 10ths?
Anarel [89]
The answer is 7.9!!!!!!
4 0
3 years ago
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Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground
Setler79 [48]
They will both hit the ground at the same time because gravitational acceleration for all objects is the same.
6 0
3 years ago
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