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Dafna11 [192]
3 years ago
10

How long does it take for an investment to double in value if it is invested at 10​% compounded monthly question mark monthly? 

Compounded​ continuously?
Mathematics
1 answer:
Margaret [11]3 years ago
7 0
The first step to determining the answer to this item is to calculate for the effective interest using the equation,

                  ieff = (1 + i/m)^m - 1
where ieff is the effective interest, i is the given interest and m is the number of compounding period.


Part A: m in this item is equal to 12.
Substituting,
                ieff = (1 + 0.10/12)^12 - 1 = 0.1047

The amount of money after n years is calculated through the equation,
               An = A(1 + ieff)^n
If An/A = 2 then,
                  2 = (1 + 0.1047)^n
The value of n is 6.96 years

Part B: For the continuously compounding,
               An = Ae^(rt)
           An/A = 2 = e^(0.10t)
The value of t is equal to 6.93 years. 

Hence, the answers:
<em>Part A: 6.96 years</em>
<em>Part B: 6.93 years</em>

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Pretty sure it would be 8h x 2

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Subtract.<br> (4x + 7) - (x+1)<br> A. 3x + 8<br> B. 3x + 6<br> C. 4x + 8<br> O D. 4x + 6<br><br> Lmk
Studentka2010 [4]

Answer:

4x + 7 - ( x + 1)

Remove the bracket

We get

4x + 7 - x - 1

= 3x + 6

That's option B

Hope this helps.

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3 years ago
Solve for x in the equation x2-8x+41=0
Alinara [238K]

Answer:

d) 4 ± 5i

Step-by-step explanation:

Here we have to use the quadratic formula.

x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}

In the given equation x^2 - 8x + 41 = 0, a =1, b = -8 and c = 41

Now plug in the given values in the above formula, we get

x = \frac{-(-8) +/- \sqrt{(-8)^2 - 4*1*41} }{2*1}

Simplifying the above, we get

x = \frac{8 +/- \sqrt{64 - 164} }{2}

x = \frac{8 +/- \sqrt{-100} }{2}

[√-100 = √-1 *√100 = i*10 = 10i] because the value of √-1 = i]

x = (8 ± 10i )/2

Now dividing by 2, we get

x = 4 ± 5i

The answer is d) 4 ± 5i

Hope you will understand the concept.

Thank you.

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3 years ago
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Equation = 2x + 7

Y-intercept = (0,7)


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