Answer
given,
interval = [-32, 32]
differentiating the given equation
hence, the above solution is not defined at x = 0
and x = 0 lie in the given interval i.e. [-32, 32]
so, at x = 0 the function is not differentiable.
Hence, mean value theorem does not apply to the given function.
Answer:
Segment EH and segment E prime H prime both pass through the center of dilation (A)
The complete question related to this found on brainly (ID:16812154) is stated below:
Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the dilation?
E(0,5) F(1,1) G(-2,1) H(0,1)
a) segment EH and segment E prime H prime both pass through the center of dilation.
b)The slope of segment EF is the same as the slope of segment E prime H prime.
c) segment E prime G prime will overlap segment EG. segment
d) EH ≅ segment E prime H prime.
Step-by-step explanation:
∆EFG = Original image
∆EFG is dilated to give ∆E'F'G'
∆E'F'G' = New image
Scale factor = 3
Center of dilation = (0,1) = H(0,1)
Coordinates ∆EFG : E(0,5) F(1,1) G(-2,1)
To determine the statement that is true about the dilation from the options,
First we would make a diagram on the coordinates of ∆EFG and center of dilation (H).
Find attached the diagram.
Length GF = 3unit
Length G'F' = 3×scale factor = 9unit
Length EH = 4unit
Length E'H' = 4×scale factor = 12unit
Then we would move 3units to the left on same line from G to get the coordinate of G'(mark the point).
Also move 3units to the right on same line from F to get the coordinate of F'(mark the point).
Both of these give length of G'F' = 9unit
Now move 8units to the top from E to get the coordinate of E'(mark the point).
From this you get length E'H' = 12unit
Draw lines connecting the three points to get ∆E'F'G'
See diagram for better understanding
From the diagram, EH and E'H' both pass through (0,1). The other options are wrong.
Therefore, Segment EH and segment E prime H prime both pass through the center of dilation (A)
