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3 years ago

The weight of one ticket is approximately 1.67 × 10-4 g. Write the numerical value without scientific notation.

Mathematics

1 answer:

mojhsa [17]3 years ago

4 0

Answer:

0.000167 g

Step-by-step explanation:

$1.67 \times {10}^{ - 4} \: g\\ \\ = 0.000167 \: g$

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Solve for x. Round to the nearest hundredth

PIT_PIT [208]

Given that the length of one leg is 6 and the angle is 40°

The hypotenuse is x.

We need to determine the value of x.

Value of x:

The value of x can be determined using the trigonometric ratio.

Thus, we have;

$cos \ \theta=\frac{adj}{hyp}$

Substituting the values, we get;

$cos \ 45^{\circ}=\frac{6}{x}$

Simplifying, we have;

$x=\frac{6}{cos \ 45^{\circ}}$

$x=\frac{6}{0.766}$

Dividing, we get;

$x\approx7.83$

Therefore, the value of x is 7.83(app.)

Hence, Option A is the correct answer.

3 0

3 years ago

Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)

vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

$y-y_0 = m(x-x_0)$ or equivalently

$y = mx+(y_0-mx_0)$ .

Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$

The slope of the tangent line is given by the derivative of the function evaluated at $x_0$ . Using the properties of derivatives, we get

$y' = \frac{-1}{x^2}$ . So evaluated at $x_0$ we get $m = \frac{-1}{x_0^2}$

Replacing the values in our previous findings we get that the y intercept is

$(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}$

The x intercept is

$\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0$

The triangle in consideration has height $\frac{2}{x_0}$ and base $2x_0$ . So the area is

$\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2$

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0

3 years ago

Algebra please help(no links)

lesya [120]

Answer:

i can't help with this specific queshtion but i do have tow say to things 1. when you post something like this make sure to crop out anything that people can see your info or anything like block out the tabs someone could see that and use it for evil be careful with this, second i do aleks to.

Step-by-step explanation:

im sorry i could not help you in the way you wanted but i hop you will be safe now!

dont make me brainlyest i dont deserve it i did not give you you answer

Have a nice day!

5 0

3 years ago

Find the slope of a line which goes through the points (2,5) and (−4,3)

natka813 [3]

Answer:

slope (m) = 0.75

Step-by-step explanation:

Slope (m) =

ΔY

ΔX

= 0.33333333333333

θ =

arctan( ΔY ) + 180°

ΔX

= 198.43494882292°

ΔX = -4 – 2 = -6

ΔY = 3 – 5 = -2

Distance (d) = √ΔX2 + ΔY2 = √40 = 6.3245553203368

Equation of the line:

y = 0.33333333333333x + 4.3333333333333

y =

1 x

+ 13

When x=0, y = 4.3333333333333

When y=0, x = -13

please mark brainliest

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Work out m and c for the line: y = 3 − x

motikmotik

Answer:

Step-by-step explanation:

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3 years ago

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