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daser333 [38]
3 years ago
9

Algebra please help(no links)

Mathematics
1 answer:
lesya [120]3 years ago
5 0

Answer:

i can't help with this specific queshtion  but i do have tow say to things 1. when you post something like this make sure to crop out anything that people can see your info or anything like block out the tabs someone could see that and use it for evil be careful with this, second i do aleks to.

 

Step-by-step explanation:

im sorry i could not help you in the way you wanted but i hop you will be safe now!

dont make me brainlyest i dont deserve it i did not give you you answer

Have a nice day!

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Value of x=4 and y=-13/3

Step-by-step explanation:

We need to solve the systems of equations

5x+3y=7 \ and \ \frac{3}{2}x-\frac{3}{4}y =9\frac{1}{4}

Solving using substitution method:

Let:

5x+3y=7---eq(1) \\ \frac{3}{2}x-\frac{3}{4}y =9\frac{1}{4}---eq(2)

Find value of x from eq(1) and put in eq(2)

5x+3y=7\\5x=7-3y\\x=\frac{7-3y}{5}

Put value of x in eq(2)

\frac{3}{2}(\frac{7-3y}{5}) -\frac{3}{4}y =\frac{37}{4}\\\frac{21-9y}{10} -\frac{3}{4}y =\frac{37}{4}\\Taking \ LCM\\\frac{21*2-9y*2-3y*5}{20}  =\frac{37}{4}\\\frac{42-18y-15y}{20}  =\frac{37}{4}\\42-33y=\frac{37}{4}*20\\42-33y=185\\-33y=185-42\\-33y=143\\y=\frac{143}{-33}\\y=-\frac{13}{3}

Now, finding value of x by putting value of y in eq(1)

x=\frac{7-3y}{5}\\x= \frac{7-3(-\frac{13}{3}) }{5}\\x=\frac{7+13}{5}\\x=\frac{20}{5}\\x=4

So, Value of x=4 and y=-13/3

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