You're looking for the extreme values of 
subject to the constraint 
.
The target function has partial derivatives (set equal to 0)
so there is only one critical point at 
. But this point does not fall in the region . There are no extreme values in the region of interest, so we check the boundary.
Parameterize the boundary of by
with 
. Then 
can be considered a function of 
alone:
has critical points where 
:
but 
for all , so this case yields nothing important.
At these critical points, we have temperatures of
so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.
I don't get it a all I tried fr
Answer: Triangles B and C
Step-by-step explanation: Because one side is divisible by 1,2,5,10 and the other side is divible by 1,3,9, etc
Download the app Photomath and write t down on a lice of paper it will give answer and how to do it
