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Valentin [98]
3 years ago
9

Game wardens use experiments to help determine the number of squirrels in a specific area. Suppose 150 squirrels are caught, tag

ged, and released back into the wild. Six weeks later, 300 squirrels are caught with 12 found to have tags. Using this information, estimate the number of squirrels in the area.

Mathematics
2 answers:
umka2103 [35]3 years ago
8 0
The total estimated population is 3750 squirrels. (Sorry for the bad writing)

Scrat [10]3 years ago
8 0

Answer:

Total number of squirrels in the area are 3750.

Step-by-step explanation:

Let, total number of squirrels = x

We are given that,

Number of squirrels tagged = 150

After six weeks, we have,

Number of squirrels caught = 200

Number of squirrels tagged out of 200 = 12

Then, we have the relation between squirrels tagged and total number of squirrels is \dfrac{12}{300}=\dfrac{150}{x}

Upon solving, we have,

\dfrac{12}{300}=\dfrac{150}{x}\\\\x=\dfrac{150\times 300}{12}\\\\x=3750

<h3>Thus, the total number of squirrels in the area are 3750.</h3>
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Answer:

3/4 of a tank =3/4(13) gal

=39/4 almost 10 gal

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As gamers progress through a video game, they earn a higher rank. In an online gaming network, gamers can see what fraction of t
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Question isn't well formatted, a picture if the question is attached below.

Answer:

1 / 4

Step-by-step explanation:

From the plot, each dot represent a gamer ; therefore, the total number of gamers will be counting all the dots ;

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Fraction of gamers that have 7 / 8 of the way to go ;

This means that they have 7/8 of the way left to proceed to next level ;

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This means the number of of people whose progress are on 1/8 ; this is 6

Hence, fraction of gamers that have 7/8 of the way to go :

6 / 24 = 1 / 4

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3 years ago
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Answer:

Fraction: 3/10

Decimal: 0.3

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Step-by-step explanation:

6 0
3 years ago
I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =16-6.2\\     =9.5

The interquartile range of the data is

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =15.5-8\\     =7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0
2 years ago
1. The height of a right triangular prism is 1 5/6 inches. Each side of the triangular base measures 10 inches, and the height o
dem82 [27]

If the height of a right triangular prism is 1 5/6 inches. The surface area of the solid formed is: 598.33 in².

<h3>Surface area</h3>

First step

Right triangular prism=1 5/6 inches= 11/6 inches

Height of the base=8 2/3 inches = 26/3 inches

Second step

Surface area = 5(10× 10) + (0.5÷ 10 × 26/3) + 3(10× 11/6)

Surface area = 5(100) +43.33+ 3(18.33)

Surface area = 500) +43.33 + 55

Surface area = 598.33 in²

Therefore the surface area of the solid formed is about 598.33 in²

Learn more about surface area here:brainly.com/question/27232541

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8 0
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