Answer:
The correct option is option (d).
Step-by-step explanation:
Logarithms are used basically to express large number.
Rules:
Here given that,
![log_5(x+30)=0](https://tex.z-dn.net/?f=log_5%28x%2B30%29%3D0)
Applying the last rule
![\Rightarrow (x+30)= 5^3](https://tex.z-dn.net/?f=%5CRightarrow%20%28x%2B30%29%3D%205%5E3)
![\Rightarrow x+30 = 125](https://tex.z-dn.net/?f=%5CRightarrow%20x%2B30%20%3D%20125)
⇒x=125-30
⇒x=95
Therefore x=95.
(x^4)(3x^3-2)(4x^2+5x)
=(3x^7-2x^4)(4x^2+5x)
=12x^9+15x^8-8x^6-10x^5
answer: 12x^9+15x^8-8x^6-10x^5
The second choise is the best choice
Answer:
B
Step-by-step explanation:
![3 \times \frac{1}{2} = \frac{7}{2}](https://tex.z-dn.net/?f=3%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B7%7D%7B2%7D%20)
![1 \times \frac{7}{10} = \frac{17}{10}](https://tex.z-dn.net/?f=1%20%5Ctimes%20%5Cfrac%7B7%7D%7B10%7D%20%20%3D%20%20%5Cfrac%7B17%7D%7B10%7D%20)
7/2 - 17/10
35/10- 17/10
18/10
![\frac{18}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B18%7D%7B10%7D%20)
1 8/10
1 4/5
Answer:
![\displaystyle 228,8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20228%2C8)
Step-by-step explanation:
![\displaystyle 2\frac{3}{5}\:sleps = 1\:quib \\ \\ 2\frac{3}{5} \times 88 = 228\frac{4}{5} = 228,8](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5Cfrac%7B3%7D%7B5%7D%5C%3Asleps%20%3D%201%5C%3Aquib%20%5C%5C%20%5C%5C%202%5Cfrac%7B3%7D%7B5%7D%20%5Ctimes%2088%20%3D%20228%5Cfrac%7B4%7D%7B5%7D%20%3D%20228%2C8)
I am joyous to assist you anytime.