1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kvv77 [185]
2 years ago
13

I need help with this

Mathematics
1 answer:
Illusion [34]2 years ago
6 0

Answer:

I'm pretty sure it's b ''the number of chargers increases''

Step-by-step explanation:

You might be interested in
HELP I WILL MARK BRAINLEST
OverLord2011 [107]

its only showing "help i will mark brainliest"..?

8 0
3 years ago
Determine the number of gallons of gas that your car holds. Find the cost of the type of gasoline that your car uses at a local
Alex17521 [72]

16 gallon tank, 2.75 $/gal so roughly 53.25


3 0
3 years ago
I need help it’s super confusing
steposvetlana [31]

Answer:

Range = 58

Mean = 25.81

Median = 17

Mode = 2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60

Upper Quartile = 11

Lower Quartile = 48

Step-by-step explanation:

Start by putting all of the values in order from least to greatest.

16, 18, 12, 9, 17, 2, 41, 48, 50, 60, 11

becomes

2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60

Range

The range is the difference between the highest and lowest value. So in this case, it's 58, because 60 - 2 = 58

Mean

The mean is another word for the average. To calculate the average, add all of the values and divide the sum by the number of values.

2 + 9 + 11 + 12 + 16 + 17 + 18 + 41 + 48 + 50 + 60 = 284

There are 11 values, so divide the sum (284) by 11:

284 / 11 = 25.8181818.

That rounds to 25.81

Median

The median is the middle value of the data set.

In 2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60 the middle value is 17. It has 5 values on each side of it.

Mode

The mode is the number that appears the most in the data set. Each value only appears once, so the mode is the entire list of numbers. 2, 9, 11, 12, 16, 17, 18, 41, 48, 50, 60

Upper Quartile

The upper quartile of a data set is the median of the numbers that are to the left of the median for the entire data set. The median is 17, so the numbers to the left are 2, 9, 11, 12, and 16. The median of those is 11 because it is in the middle. So the upper quartile is 11.

Lower Quartile

The lower quartile is found the same way the upper quartile is, but it's the median of the numbers to the <em>right</em>. The numbers to the right of 17 are

18, 41, 48, 50, and 60. The median of those is 48 because it's in the middle. So the lower quartile is 48.

5 0
3 years ago
I WILL GIVE BRAINLEST!!! 20 POINTS!!!
Alenkasestr [34]
It the answer would be 51.41
3 0
2 years ago
Read 2 more answers
Aidan ran 712 of a mile, then took a break before running another 12 of a mile. How far did Aidan run in all?
sdas [7]

Answer:

Is that supposed to be

7 1/2? If so, answer is 8

Step-by-step explanation:

7 1/2 + 1/2=8

7 0
3 years ago
Other questions:
  • studying enzyme kinetics encounter formulas of the form f(x) = (K/V)x+1/V, where and are constants. Use this infombon to answer
    10·1 answer
  • A person has 17 coins, all nickels and dimes, worth $1.25. How many nickels are there?
    8·1 answer
  • HELP PLEASE? What is the coefficient of y in expansion of (y+4)^4 ?
    14·1 answer
  • Find the area in square meters 5m 4m 2m
    15·1 answer
  • What is the F.O.I.L method in Algerbra 1?
    15·2 answers
  • −30=5(x+1) please simplify this for khan academy. org
    12·2 answers
  • Find the lowest common denominator for the fractions shown.
    11·1 answer
  • Dalvin has a toy car collection of 200 toy cars. He keeps 194 of the toy cars on his wall. What percentage of Dalvin's toy car c
    8·1 answer
  • A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π
    12·1 answer
  • Two long strips of paper are each 2 inches wide, and they overlap so that the angle between the strips is 30 degrees. What is th
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!