Step-by-step explanation:
4+6+5=15
15-1=14
2/14
1/7
The prime factorisation of 81 is 3^4(because 3*3*3*3 four times =81)
do not change the rest 3^4 m^2 x^3
The given formula is f(x) = 20(1.2)^x
The formula is the starting amount multiplied by 1 + the percentage raised to the number of weeks.
A) the percent increase is 20% ( 1.2 in the formula is 1 +20% as a decimal)
B) the original amount is $20
C) for 2 weeks, replace x with 2 and solve:
20(1.2)^2
20(1.44) = $28.80
After 2 weeks the coupon is $28.80
D) To solve for the number of weeks (x) set the equation equal to $100:
100 = 20(1.2)^x
Divide both sides by 20:
5 = 1.2^x
Take the natural logarithm of both sides:
ln(5) = ln(1.2^x)
Use the logarithm rule to remove the exponent:
ln(5) = x ln(1.2)
Divide both sides by ln(1.2)
x = ln(5) / ln(1.2)
Divide:
X = 8.83
At 8.83 weeks the coupon would be $100, so after 9 weeks the coupon would be greater than $100
The answer is 9 weeks.
Answer:
x=26/3 because you need to comine like terms as usual
For the answer to the question above, <span>Well, first let us put up a functional equation. </span>
<span>Since this is an exponential function, it'll be: f(t)=54,000*1.03^t </span>
<span>But we want to know how many wolves there were 10 years ago. </span>
<span>For that, we simply "turn time around", as in: f(t)=54,00*1.03^-t </span>
<span>This displays a decreasing number of wolves, as you turn back time. </span>
<span>Now we simply calculate 54,000*1.03^-10 </span>
<span>which is approximately 40,200?</span>
