There are many polynomials that fit the bill,
f(x)=a(x-r1)(x-r2)(x-r3)(x-r4) where a is any real number not equal to zero.
A simple one is when a=1.
where r1,r2,r3,r4 are the roots of the 4th degree polynomial.
Also note that for a polynomial with *real* coefficients, complex roots *always* come in conjugages, i.e. in the form a±bi [±=+/-]
So a polynomial would be:
f(x)=(x-(-4-5i))(x-(-4+5i))(x--2)(x--2)
or, simplifying
f(x)=(x+4+5i)(x+4-5i)(x+2)^2
=x^4+12x^3+77x^2+196x+164 [if you decide to expand]
Answer:
261 km
Step-by-step explanation:
given,s=constant
d1/T1=d2/T2
d1=90km,t1=50 min
d2=? ,t2=(120+25)min
=145min
therefore,d2=(90×145)/50
=261 km
<h3>
Answer: 19</h3>
==============================================================
Explanation:
T is the midpoint of PQ, which means T splits PQ into two equal parts. Those parts being PT and TQ.
Set them equal to each other and solve for x.
PT = TQ
3x+7 = 7x-9
3x-7x = -9-7
-4x = -16
x = -16/(-4)
x = 4
So,
PT = 3x+7 = 3*4+7 = 19
TQ = 7x-9 = 7*4-9 = 19
Both PT and TQ are 19 units long to help confirm the answer.
Step-by-step explanation:
by adding :
e=_4
d=24.....
