Answer:
44
Step-by-step explanation:
Answer:
16. 142 deg
17. 23 deg
18. 134 deg
19. 38 deg
Step-by-step explanation:
16.
m(arc)QT = 2m<QST = 2 * 71 = 142
17.
m<STR = (1/2)m(arc)RS = (1/2)46 = 23
18.
RT is a diameter since it includes the center of the circle, point X.
m(arc)RST = 180
m(arc)RS + m(arc)ST = m(arc)RST
46 + m(arc)ST = 180
m(arc)ST = 134
19.
RT is a diameter since it includes the center of the circle, point X.
m(arc)RQT = 180
m(arc)RQ + m(arc)QT = m(arc)RQT
m(arc)RQ + 142 = 180
m(arc)RQ = 38
Hello,
let's assume a the width, b the heigth.
sin 30°=a/26=1/2==>a=26/2=13 (in)
cos 30°=b/26=√3/2==>b=26*√3 / 2=13√3≈22.51666.... (in)
The base is 5 because 4×5 is 20
We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.
First of all, we will draw a triangle as shown in the attachment.
We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.
We know that sine relates opposite side of right triangle to hypotenuse.


Using inverse sine or arcsin, we will get:


Upon rounding to nearest degree, we will get:

Therefore, the measure of angle J is approximately 24 degrees.