Finding a parametric description of the solution set of a linear system is the same as solving the system.Choose the correct ans
1 answer:
Answer:
The answer is "Choice B".
Step-by-step explanation:
Please find the complete question in the attached file.
In this question, in all choices, the choice (B) is Correct because in the declaration of the statement Only when the process has had at least another answer could a candidate solution for more than just a linear model explicitly uses a parametric description that's why the given statement is true.
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for
when a=1, then the value of c that will make the quadratic a perfect square (allows you to complete the square) is
given x^2+x
b=1
so
answer is C
Answer:
Step-by-step explanation:
Let's start defining the random variables for this exercise :
'' The proportion of the particulates that are removed by the first pass ''
'' The proportion of what remains after the first pass that is removed by the second pass ''
'' The proportion of the original particulates that remain in the sample after two passes ''
We know the relation between the random variables :
We also assume that and
are independent random variables with common pdf.
The probability density function for both variables is for
and
otherwise.
The first step to solve this exercise is to find the expected value for and
.
Because the variables have the same pdf we write :
Using the pdf to calculate the expected value we write :
Where ∞ and
- ∞ (because we integrate in the whole range of the random variable). In this case, we will integrate between
and
⇒
Using the pdf we calculate the expected value :
⇒
Now we need to use some expected value properties in the expression of ⇒
⇒
Applying the expected value properties (linearity and expected value of a constant) ⇒
Using that and
have the same expected value
and given that
and
are independent random variables we can write
⇒
⇒
Using the value of calculated :
We find that the expected value of the variable is