Answer:
Option C
-5, -2, 1, 3
Step-by-step explanation:
to get the list that orders the numbers from the least to the greatest, we need to, first of all, know the smallest and the largest numbers.
The largest number is easy to guess - it is undoubtedly 3.
However, the smallest number may be a bit tricky because we are dealing with negative numbers. When dealing with negative numbers, the numbers with greater magnitudes are actually smaller. This means that -5 is less than -3, which is less than -2, and so on.
Coming back to our question, we can now order the numbers as -5, -2, 1, 3 which is option C
I believe there is no such AP...
Recursively, this sequence is supposed to be given by
so that
has to be an integer, which means there are 4 possible cases.
Case 1: 
and 
. But
Case 2: 
and 
. But
Case 3: 
and 
. But
Case 4: 
and 
. But
<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
X
X+2
X+4
Those are 3 consecutive odd integers
-9 and another number (i dont have paper rn sorry)
