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3 years ago

Kate has 10 stickers. One half of them are purple. How many of Kate’s stickers are purple?

Mathematics

1 answer:

stiks02 [169]3 years ago

8 0

Answer:

Step-by-step explanation:

Half of ten is five so Kate’s has five purple stickers

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Ayuda aqui en este ejercicio (2x+8)2 (el ultimo 2 va elevado)

Ksenya-84 [330]

Answer:

4x^2+32x+64

Step-by-step explanation:

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2 years ago

Y is directly related to x and y is 81 when x is 27 the constant of.variation is

suter [353]

Answer:

The constant of variation is 3

Step-by-step explanation:

Given.

$y=81$

$x=27$

And y is directly related to x

$y$ ∝ $x$

Here k is constant of variation

$y=kx$

$k=\frac{y}{x}$ --------------(1)

Put the $y$ and $x$ value in equation 1.

$k=\frac{81}{27}$

$k=3$

So, the constant of variation is 3.

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2 years ago

Aproxima a las unidades de mil y obtén los resultados estimados

zhenek [66]

Answer:

Step-by-step explanation:

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2 years ago

Evaluate: -16 - w, when w = -23.

Rus_ich [418]

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2 years ago

Read 2 more answers

Let g(x) = 2x and h(x) = x^2 + 4. Find the value.(g o h) (0)a) 4b) 8c) 0d) 16

Paul [167]

$\begin{gathered} \text{Given} \\ g(x)=2x \\ h(x)=x^2+4 \end{gathered}$

Solve for (g o h)(x)

$\begin{gathered} (g\circ f)(x)=g\big(f(x)\big) \\ (g\circ f)(x)=g(x^2+4) \\ (g\circ f)(x)=2(x^2+4) \\ (g\circ f)(x)=2x^2+8 \end{gathered}$

Next substitute x = 0

$\begin{gathered} (g\circ f)(x)=2x^2+8 \\ (g\circ f)(0)=2(0)^2+8 \\ (g\circ f)(0)=8 \end{gathered}$ $\text{Therefore, }(g\circ f)(0)=8$

5 0

1 year ago