Answer:
E=2.8 m-40
Step-by-step explanation:
We konw that 30°E=25°M and 310°E=125°M
so if we want to write an ecuation that linearly relates E with M, we can use the formula of the line that crosses two points:
Y-y1= (y2-y1)/(x2-x1)*(X-x1)
In thts case:
- y1= E1= 30
- y2= E2=310
- x1= M1= 25
- x2=M2=125
so
E-E1= (E2-E1)/(M2-M1)* (M-M1)
E-30 = (310-30)/(125-25)*(M-25)
E-30 =280/100 *(M-25)
E-30 =2.8 M- 280*25/100
E-30 =2.8 M-70
E= 2.8 M-70+30
E=2.8 M-40
Good luck!
They can line up every 10 yards because there are 120 yard on a football field
12 cheerleaders gives you 1 every 10 yards
Centre of circle = (-2, -3)
Equation of the circle:
( x - ( -2) )² + ( y - (-3) )² = (√2/4)²
(x + 2)² + (y + 3)² = 1/8 (Answer D)
Answer:
<h3>6 days</h3>
Step-by-step explanation:
Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n
To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n
425 ≥ 125 + 50n
Subtract 125 from both sides
425 - 125 ≥ 125 + 50n - 125
300≥ 50n
Divide both sides by 50
300/50≥50n/50
6 ≥n
Rearrange
n≤6
<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>
<em></em>
Answer:
$32.5
Step-by-step explanation:
I hope this helps.
