Answer: the length of each of the two equal sides is 25 centimeters
Step-by-step explanation:
Let x represent the length of each of the two equal sides. This means that the total length of the two longer sides is 2x.
Let y represent the length of the third side.
The perimeter of a triangle is expressed as the sum of the length of each side of the triangle. The perimeter of the isosceles triangle is 65 centimeters. It means that
2x + y = 65 - - - - - - - - - 1
Each of the equal sides is 10 centimeters longer than the third side. This means that
x = y + 10
Substituting x = y + 10 into equation 1, it becomes
2(y + 10) + y = 65
2y + 20 + y = 65
2y + y = 65 - 20
3y = 45
y = 45/3 = 15
Substituting y = 15 into x = y + 10, it becomes
x = 15 + 10 = 25
Angle 5 = 117° because it is vertical to angle 8
Angle 7 = 63° because it is symmetrical to angle 5
Angle 6 = 63° because it is vertical to angle 7.
Angle 1 = 117° because it is corresponding to angle 5.
Angle 2 = 63° because it is corresponding to angle 6.
Angle 3= 117° because it is corresponding to angle 8.
Angle 4 = 63° because it is corresponding to angle 7.
Answer:
-9xy+16x
Step-by-step explanation:
x(y-2) +3x(6-y) -7xy
Distribute
xy -2x +18x-3xy -7xy
Combine like terms
-9xy+16x
Answer:
$40.4
Step-by-step explanation:
The regular price of the fishing rod is $97
There is a 60% discount from that price.
The discount is equal to 60% of $97 which is equal to .60 * $97 which is equal to $58.2
Discount is like a markdown, so subtract $58.2 from the price of the item before the change to get $97 - $58.2 = $38.8
This is the price of the item before tax is applied.
Now you apply the sales tax of 4%.
4% of $38.8 is equal to .04 * $38.8 which is equal to $1.552
Tax is like a markup, so add $1.552 to the price of the item before tax was applied to get a selling price of $38.8 + $1.552 which is equal to $40.352
Round it up and the answer is $40.4
Answer:
.
Step-by-step explanation:
A point of the form 
belongs to the graph of this function, 
, if and only if the equation of this function holds after substituting in 
and 
.
The question states that the point 
belongs to the graph of this function. Thus, the equation of this function, , should hold after substituting in 
and 
:
.
.
Solve this equation for the constant 
:
.
Thus, .
