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levacccp [35]
3 years ago
13

Solve the inequality. -6b - 8 > 34

Mathematics
1 answer:
Shkiper50 [21]3 years ago
4 0
Hello!

You can solve inequalities just like equations.

-6b-8>34
-6b>42
b>-7

The solution to the inequality is b>-7.

I hope this helps!
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An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
Greg swam 4 kilometers against the current in the same amount of time it took him to swim 16 kilometers with the current. The ra
ad-work [718]

Answer:

5 kmph

Step-by-step explanation:

Given: Greg swam 4 kilometers against the current.

            Greg swam 16 kilometers with the current.

            Rate of the current was 3kmph.

Lets assume the speed of greg swimming with no current be "x".

∴ Speed of swimming against current= (x-3)\ kmph

   Speed of swimming with current= (x+3)\ kmph

As given, it took same amount of time to swim both with current and against current.

∴ Forming an equation to find the value of x, which is speed of greg swimming with no current.

We know, Time= \frac{Distance}{Speed}

⇒ \frac{4}{(x-3)} = \frac{16}{(x+3)}

Multiplying both side by (x+3) and (x-3)

⇒4\times (x+3)= 16\times (x-3)

Using distributive property of multiplication.

⇒ 4x+12= 16x-48

Subtracting both side by 4x and adding by 48.

⇒60= 12x

Dividing both side by 12

⇒x= \frac{60}{12} = 5\ kmph

Hence, Greg can swim at the rate of 5kmph with no current.

7 0
4 years ago
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