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2 years ago

Find the values of x and y X = Y=

Mathematics

1 answer:

labwork [276]2 years ago

3 0

Answer:

Find the values of x and y

X =60

Y=60

60°

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A rain gutter is made from sheets of aluminum that are 18 inches wide by turning up the edges to form right angles. Determine th

mr Goodwill [35]

The answer is C. 4.5 in

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2 years ago

What’s the answer ??

ollegr [7]

Answer:

Step-by-step explanation:

radius r = 10/2 = 5 ft

height h = 5 ft

Volume = πr²h = π(5²)(5) = 125π ≈ 392.7 ft³

5 0

2 years ago

Can someone help me on this

Cerrena [4.2K]

Answer:

2x+h

Step-by-step explanation:

f(x+h) means that wherever there's an x in the function f(x) we plug in a x+h

we have

(x+h)²+9

Let's start with the numerator

(x+h)²+9-(x²+9)

Distribute the exponent

x²+2xh+h²+9-x²-9

Which gives us

2xh+h²

Divide the whole thing by h to give us

2x+h

4 0

3 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago

This is not math but i need help <br><br><br>what is a allusion

wariber [46]

Answer:

an expression designed to call something to mind without mentioning it explicitly; an indirect or passing reference.

Step-by-step explanation:

4 0

3 years ago

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